如何创建一个接受变量列表的 if 语句条件？答案

【问题标题】：How to create an if statement condition that would accept the list of variables?如何创建一个接受变量列表的 if 语句条件？
【发布时间】：2020-11-12 02:34:36
【问题描述】：

如何在 if 语句中创建一个接受变量列表并打印出可被 5 整除的数字的条件？`

firstNumber = input("Write the First Number: ")
secondNumber = input("Write the Second Number: ")
thirdNumber = input("Write the the Third Number: ")
fourthNumber = input("Write the the Fourth Number: ")
list1 = [firstNumber, secondNumber, thirdNumber, fourthNumber]

def divisibleByFive():
    for x in list1:
        if x%5 == 0:
            print(x)

divisibleByFive()

【问题讨论】：

将输入字符串转换为整数：firstNumber = int(input("Write the First Number: "))等

标签： python python-3.x list if-statement user-input

【解决方案1】：

在函数中获取它作为参数并在调用时传递：

firstNumber = input("Write the First Number: ")
secondNumber = input("Write the Second Number: ")
thirdNumber = input("Write the the Third Number: ")
fourthNumber = input("Write the the Fourth Number: ")
list1 = [firstNumber, secondNumber, thirdNumber, fourthNumber]

def divisibleByFive(l1):
    for x in l1:
        if int(x)%5 == 0:
            print(int(x))

divisibleByFive(list1)

不喜欢路过？使用全局变量，但这太过分了:-(

firstNumber = input("Write the First Number: ")
secondNumber = input("Write the Second Number: ")
thirdNumber = input("Write the the Third Number: ")
fourthNumber = input("Write the the Fourth Number: ")
list1 = [firstNumber, secondNumber, thirdNumber, fourthNumber]

def divisibleByFive():
    global list1
    for x in list1:
        if int(x)%5 == 0:
            print(int(x))

divisibleByFive()

【讨论】：

如果您打算修改列表，您只需要global - 这里不需要。代码的主要问题是输入数据是字符串，在使用%运算符之前需要转换为int。