如何在 Python 中分隔名称和分数列表？

Question

所以我有这个任务，我必须从文本文件中计算玩家的分数，然后打印分数。如何拆分名称和分数并计算特定名称的分数？并且名称必须按字母顺序排列。

我试过这个：

file = input("Enter the name of the score file: ")
    print("Contestant score:")
    open_file = open(file, "r")
    list = open_file.readlines()
    open_file.close()
    for row in sorted(list):
        row = row.rstrip()
        contestant = row.split(" ")
    if contestant[0] == contestant[0]:
        total = int(contestant[1]) + int(contestant[1])
        print(contestant[0], total)
    print(row)

文本文件示例：

sophia 2

sophia 3

peter 7

matt 10

james 3

peter 5

sophia 5

matt 9

程序应该是这样的：

james 3

matt 19

peter 12

sophia 10

而我目前的输出是：

sophia 10

sophia 5

Answer 1

我建议制作一本字典：

# Open Text File
file = input("Enter the name of the score file: ")
print("Contestant score:")
open_file = open(file, "r")
lines = open_file.readlines()

# Convert into one single line for ease
mystr = '\t'.join([line.strip() for line in lines])

# Split it and make dictionary
out = mystr.split()
entries = dict([(x, y) for x, y in zip(out[::2], out[1::2])])

# Unsorted Display
print(entries)

# Sorted Display
print(sorted(entries.items(), key=lambda s: s[0]))

输出：

[('james', '3'), ('matt', '9'), ('peter', '5'), ('sophia', '5')]

您可以以任何您喜欢的形式显示/保存此字典，例如 CSV、JSON 或仅保留它。

Answer 2

您可以为此使用collections.defaultdict。

代码：

from collections import defaultdict

file = input("Enter the name of the score file: ")
results = defaultdict(int)
with open(file, "r") as file:
    # Gather results from each line.
    for line in file:
        name, points = line.split()
        results[name] += int(points)

# Print the results dict.
print("Contestant score:")
for name in sorted(results.keys()):
    print(name, results[name])

这适用于 Python 3。

输出：

Enter the name of the score file: input.txt
Contestant score:
james 3
matt 19
peter 12
sophia 10

Answer 3

您可以使用字典来存储每个玩家的总分。

from collections import defaultdict
scores=defaultdict(int)
with open('score.txt','r') as f:
    for line in f:
        if line.strip():
            key,val=line.split()
            scores[key]+=int(val)

print(*sorted(scores.items()),sep='\n')

---

输出：

('james', 3)
('matt', 19)
('peter', 12)
('sophia', 10)

Answer 4

你可以使用类似的东西：

import os
from collections import defaultdict
file = input("Enter the name of the score file: ").strip()
results = defaultdict(int)
if(os.path.isfile(file)):
    with open(file) as f:
        for row in sorted([x.strip() for x in list(f) if x]):
            line = row.split()
            if len(line) == 2:
                results[line[0]] += int(line[1])

        print("Contestants scores:")
        for k, v in results.items():
            print(k, v)
else:
    print("File not found", file)

---

Contestants scores:
james 3
matt 19
peter 12
sophia 10

---

demo

Answer 5

我只使用标准字典（不是collections.defaultdict）制定了一个解决方案，所以我想我也会发布它。

Python 3

代码：

file = input("Enter the name of the score file: ")
print("Contestant score:")

gamer_dict = {}
with open(file, 'r') as infile:
    for row in infile:
        splits = row.split(" ")
        name = splits[0].strip()
        score = int(splits[1].strip())
        if name not in gamer_dict:
            gamer_dict[name] = score
        else:
            gamer_dict[name] += score

for k,v in sorted(gamer_dict.items()):
    print(k,v)

输出：

Enter the name of the score file: gamers.txt
Contestant score:
james 3
matt 19
peter 12
sophia 10