【发布时间】:2021-11-09 10:23:26
【问题描述】:
我有一些单选按钮。根据选择的单选按钮,我希望有不同的组合框值。我不知道我该如何解决这个问题。在进一步的步骤中,我想创建更多的组合框,这些组合框取决于第一个的值。
以下代码创建用户列表,但它没有显示在组合框中。
对我来说,很难理解函数的正确位置,以及我是否需要 lambda 函数或绑定。
import tkinter as tk
from tkinter import ttk
import pandas as pd
import os
global version
global df_MA
df_MA = []
class Window(tk.Toplevel):
def __init__(self, parent):
super().__init__(parent)
self.geometry('300x100')
self.title('Toplevel Window')
self.btn = ttk.Button(self, text='Close',command=self.destroy).pack(expand=True)
class App(tk.Tk):
def __init__(self,*args, **kwargs):
super().__init__()
# def load_input_values(self):
def set_department(department):
if department == "produktion":
working_df_complete = path_input_produktion
if department == "service":
working_df_complete = path_input_service
working_df_complete = pd.read_excel(working_df_complete)
working_df_complete = pd.DataFrame(working_df_complete)
'''set worker df'''
df_MA = working_df_complete.loc[:,'MA']
df_MA = list(df_MA.values.tolist())
def select_working_step():
return
'''Define Variable Bereich aofter clicking of radio button '''
'''SEEMS TO ME UNECCESSARY COMPLICATED, but I dont't know how to do it properly. I am no progammer'''
border = 10
spacey = 10
'''paths for input file'''
path_input_produktion = os.path.abspath('input_data\werte_comboboxen_produktion.xlsx')
path_input_service = os.path.abspath('input_data\werte_comboboxen_service.xlsx')
self.geometry('500x600')
'''Variablen for department'''
department = tk.StringVar()
department.set(" ")
'''place Frame department'''
self.rb_frame_abteilung = tk.Frame(self)
'''Radiobuttons for department'''
rb_abteilung_produktion = tk.Radiobutton(self.rb_frame_abteilung, text="Produktion", variable= department,
value="produktion", command= lambda: set_department(department.get()))
rb_abteilung_service = tk.Radiobutton(self.rb_frame_abteilung, text="Service", variable= department,
value="service", command= lambda: set_department(department.get()) )
rb_abteilung_produktion.pack(side="left", fill=None, expand=False, padx=10)
rb_abteilung_service.pack(side="left", fill=None, expand=False, padx =10)
self.rb_frame_abteilung.grid(row=5, column=1, sticky="nw", columnspan=99)
self.label_user = ttk.Label(self, text='user').grid(row=15,
column=15, pady=spacey,padx=border, sticky='w')
self.combobox_user = ttk.Combobox(self, width = 10, value= df_MA)
self.combobox_user.bind("<<ComboboxSelected>>", select_working_step)
self.combobox_user.grid(row=15, column=20, pady=spacey, sticky='w')
if __name__ == "__main__":
app = App()
app.mainloop()
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【问题讨论】:
-
请edit 寻求minimal reproducible example。这个问题的代码太多了。
-
希望现在一切都好!??
-
不,我的答案比你的minimal reproducible example 少。请抓紧时间,否则下次可能得不到答复。人们不想阅读您的所有代码,这需要时间。请阅读How to Ask
标签: python python-3.x tkinter bind