在Tkinter中获取文件名并选择后显示答案

【问题标题】：Get file name in Tkinter and display it after chosing在Tkinter中获取文件名并选择后显示
【发布时间】：2021-11-22 08:42:31
【问题描述】：

程序应该创建一个窗口，在中心放置一个按钮。当按下按钮打开一个需要选择文件的系统窗口时，应在按钮下方写入文件名。我在最后一部分遇到了问题，文件名仅显示在控制台上，试图让filename 失效，但出现错误。

import tkinter as tk
from tkinter import filedialog
from tkinter.constants import CENTER
from tkinter.filedialog import askopenfilename

def UploadAction(event=None):
    filename = filedialog.askopenfilename()
    print('Selected:', filename)

root= tk.Tk()

canvas1 = tk.Canvas(root, width = 300, height = 300)
canvas1.pack()
    
button1 = tk.Button(text='Click Me',command=UploadAction, bg='brown',fg='white')
canvas1.create_window(150, 150, window=button1)
button1.place (relx = 0.5, rely = 0.5, anchor=CENTER)
canvas1.create_text(relx = 0.5, rely = 0.7, anchor=CENTER, text= filename, fill="black", font=('Helvetica 15 bold'))

root.mainloop()

【问题讨论】：

一种解决方案将filename 设为全局（来源：w3schools.com/python/python_variables_global.asp）
button1.place(...) 在使用canvas1.create_window(...) 将button1 放入画布后不应执行。执行canvas1.create_text(..., text=filename, ...) 时，filename 也未定义。

标签： python python-3.x tkinter

【解决方案1】：

您似乎正在尝试在画布上显示文本，但有一种更简单的方法是使用标签并更改其文本：

import tkinter as tk
from tkinter.filedialog import askopenfilename

filename = None
def UploadAction(event=None):
    filename = askopenfilename()
    print('Selected:', filename)
    # Change text of label
    label1['text'] = filename

root= tk.Tk()
    
button1 = tk.Button(text='Click Me', command=UploadAction, bg='brown', fg='white')
button1.pack(padx=2, pady=5)
label1 = tk.Label(text='Please choose a file')
label1.pack(padx=2, pady=2)

root.mainloop()

如果您只想显示文件名：

import tkinter as tk
from tkinter.filedialog import askopenfilename

filename = None
def UploadAction(event=None):
    filename = askopenfilename()
    # Cut path to the file off
    filename = filename.split('/')[len(filename.split('/'))-1]
    print('Selected:', filename)
    label1['text'] = filename

root= tk.Tk()
    
button1 = tk.Button(text='Click Me', command=UploadAction, bg='brown', fg='white')
button1.pack(padx=2, pady=5)
label1 = tk.Label(text='Please choose a file')
label1.pack(padx=2, pady=2)

root.mainloop()

【讨论】：