检查 OrderedDict 中是否存在键

Question

我正在处理从 python2 到 python3 的代码迁移。我对 Python 中的 OOP 和 OrderedDict 没有太多经验。这是我无法解决的问题。 before 也有人问过类似的问题，但似乎对这种情况没有任何作用。我有以下代码：

for row in rows:
    new_ = dummy(row.attr, row.error_type, row.array_agg_1,
                   row.with_error, row.total, row.level, row.order_)

    if new_ in result[n.id]: # <- never becomes true
         print('I am in the if')
         if new_.with_error is not None:
             result[n.id][new_][1] += new_.with_error
             result['total'][new_][1] += new_.with_error
    else:
         print('I am in the else')
         if new_.with_error is not None:
             result[n.id][new_] = [new_.attr, new_.with_error]

此代码在 python2 中有效。但是，python3 版本无法执行外部if 语句。

result[n.id] 是一个OrderedDict，看起来像这样：

#an example of result[n.id]
>>> ([(Eclipse Required Items'nce'[1540972], ['Eclipse Required Items', 1, 1, [1540972], 'nce', 1, 1681]), 
(Other Story Tab Info learned/discovered documentation and accuracy'nce'[1540973], ['Other Story Tab Info learned/discovered documentation and accuracy', 1, 1, [1540973], 'nce', 1, 1684]),
(Other (please provide detail in Comments section)'bce'[1541001], ['Other (please provide detail in Comments section', 1, 1, [1540973], 'bce', 1, 1684]
(Other Static bar information was documented'nce'[1540974], ['Other Static bar information was documented', 1, 1, [1541001], 'nce', 1, 1707])])

#type of result[n.id]
>>> <class 'collections.OrderedDict'>

new_ 看起来像这样：

#print(new_)
Other (please provide detail in Comments section)'bce'[1541001]

#print(type(new_))
<class 'smd.lib.asynch.calibration.dummy'>

我尝试过的事情

if str(new_) in str(result[n.id]):

它可以在内部使用 KeyError 失败，我不确定这是否是最好的方法。此外，它可能会破坏软件的其他功能。

if new_ in result[n.id].keys():

不起作用。任何解决问题的帮助和指导将不胜感激。

dummy 类如下所示：

class dummy(object):

    def __init__(self, attr, error_type, path, with_error=None, total=None,
                 level=None, order=None):
        self.attr = attr
        self.error_type = error_type
        self.path = path
        self.with_error = with_error
        self.total = total
        self.level = level
        self.order = order

    def __cmp__(self, other):
        return not (
            self.attr == other.attr and self.error_type == other.error_type
            and self.path == other.path
        )

    def __base_repr__(self):
        return "{0}{1}{2}".format(self.attr, self.error_type, self.path)

    def __hash__(self):
        return hash(self.__base_repr__())

    def __repr__(self):
        return self.__base_repr__()

Answer 1

在 Python 3 中，__cmp__ 不再使用。 您需要在您的班级中实现__eq__ 并删除__cmp__