点击后有没有办法在 PySimpleGUI 中更新网格

Question

大家好，

我一直致力于使用 PySimpleGUI 为我的井字游戏创建 GUI。我的代码如下：

import PySimpleGUI as sg
import random 

board_layout1 = {(2,0):" ", (2,1):" ", (2,2): " ", (1,0): " ", (1,1): " ", (1,2): " ", (0,0): " ", (0,1): " ", (0,2): " "}

电路板布局基于：

Diagram

然后我创建了一个界面来接收用户输入（即名称并选择 X 或 O 符号）。

layout = [      
        [sg.Text("Please enter your Name and your opponent's name")],    
        [sg.Text('Name', size=(15, 1)), sg.InputText('')],      
        [sg.Text('Name of opponent', size=(15, 1)), sg.InputText('')],
        [sg.Frame(layout=[
        [sg.Radio('X', "RADIO1", default=True, size=(10,1)), sg.Radio('O', "RADIO1")]], title='Options',title_color='red', relief=sg.RELIEF_SUNKEN, tooltip='Use these to set flags')],
        [sg.Submit(), sg.Cancel()]      
        ]

window = sg.Window('Tic Tac Toe Game').Layout(layout)         
button, events = window.Read() 
print(events)
window.close()     


player1, player2, player1_event, player2_event = events[0], events[1], events[2], events[3]

player1 和 player2 将返回他们的名字。 Player1_event 和 player2_event 将返回 True 或 False。当我使用复选框时，如果我选中它，events2 将为 True，而 events[3] 将为 False。

然后我分别分配标记。

if player1_event == True:
    player1_marker, player2_marker = ("X", "O")
else:
    player1_marker, player2_marker = ("O", "X")

现在，我将为板子创建 GUI。

def board_gui():    
    max_row = max_col = 3

    layout =  [[sg.Button(' ', size=(8, 4), key=(i,j), pad=(0,0)) for j in range(max_col)] for i in range(max_col)]

    window = sg.Window('Tictactoe', layout)
    button, events = window.Read()
    return button 
    window.close()

接下来（问题出在哪里），我创建了相应地更新板的函数。因此，假设 play1 首先开始并且他决定选择“X”作为他的标记。他选择了第一个网格并单击它。它标记了“X”。所以下一次点击应该属于play2，它的标记是'O'。我的代码似乎在为第二次点击更新标记时出现问题。

我做了什么：

def board_gui_update(marker):   
    max_row = max_col = 3

    layout =  [[sg.Button(' ', size=(8, 4), key=(i,j), pad=(0,0)) for j in range(max_col)] for i in range(max_col)]
    window = sg.Window('Tictactoe', layout)
    while True:
        button, events = window.Read()
        if button in (None, 'Exit'):
            break
        window[button].update(marker)

    window.close()

我尝试过的：

def board_gui_update(marker):   
    max_row = max_col = 3
    layout =  [[sg.Button(' ', size=(8, 4), key=(i,j), pad=(0,0)) for j in range(max_col)] for i in range(max_col)]
    window = sg.Window('Tictactoe', layout)
    while True:
        button, events = window.Read()
        if button in (None, 'Exit'):
            break
        if marker == player1_marker:
            turn = player1
            if turn == player1:
                window[button].update(player1_marker)
                turn = player2
            else:
                window[button].update(player2_marker)
        else:
            if marker == player2_marker:
                turn = player2
                if turn == player2:
                    window[button].update(player2_marker)
                turn = player1
            else:
                window[button].update(player1_marker)

    window.close()

这里似乎也不起作用。我查看了涉及 tkinter 的文档和解决方案，但似乎没有任何东西能够更新标记。

您可以在此snapshot 中查看问题。

Answer 1

看看这是否符合您的要求。每次你点击一个正方形，它都会变成一个新的标记。我认为您是在说您无法更改按钮上显示的值。该程序向您展示了如何做到这一点。

import PySimpleGUI as sg

layout = [[sg.B(' ', size=(8,4), key=(i,j)) for i in range(3)] for j in range(3)]

window = sg.Window('Tic Skeleton', layout)

while True:             # Event Loop
    event, values = window.read()
    print(event, values)
    if event in (None, 'Exit'):
        break
    current_marker = window[event].get_text()
    window[event].update('X' if current_marker == ' ' else 'O' if current_marker == 'X' else ' ')
window.close()

Answer 2

根据上面的示例，我制作了可以在“O”和“X”之间交替的代码。 我使用了一个在 False 和 True 之间交替的变量，以及两个标识 window[event].get_text() 内部值的 if，对其进行分析并更改变量。

import PySimpleGUI as sg

layout = [[sg.Button(' ', size=(8,4)), sg.Button(' ', size=(8,4)), 
           sg.Button(' ', size=(8,4))],
          [sg.Button(' ', size=(8,4)), sg.Button(' ', size=(8,4)), 
           sg.Button(' ', size=(8,4))],
          [sg.Button(' ', size=(8,4)), sg.Button(' ', size=(8,4)), 
           sg.Button(' ', size=(8,4))]]

turn = True
window = sg.Window('Tic Tac Toe', layout)

while True:    # Event Loop
    event, values = window.read()
    print(event, values) #Just for development purposes.
    if event in (None, 'Exit'):
        break
    current_marker = window[event].get_text()
    # I placed all updates conditionals inside this, works better than 
    # individuals 'ifs' for each of they.
    window[event].update('X' if current_marker == ' ' and 
                         turn == True else 'O' if current_marker == ' ' and 
                         turn == False else 'X' if current_marker == 'X' 
                         else 'O' if current_marker == 'O' else ' ') 
    # The conditionals that change which value should be inserted.
    if window[event].get_text() == 'X':
        turn = False                       
    elif window[event].get_text() == 'O':
        turn = True

window.close()