在python的字符串列表中找到确切的单词列表？答案

【问题标题】：find the exact list of words in list of strings in python?在python的字符串列表中找到确切的单词列表？
【发布时间】：2021-03-05 14:13:51
【问题描述】：

我有两个字符串列表：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

我想检查grids 在links 中的内容。所以我为此写了一个程序：

import re

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        result = re.findall('\\b' + search + '\\b', text, flags=re.IGNORECASE)
        print(result)

输出：

['north']
['north']
[]
[]
[]
[]
['northeast']
[]
[]
['south']

我几乎得到了输出，但不明白为什么我会在输出中得到那些空白，所以我可以为这个获得更简单和干净的替代方案吗？

【问题讨论】：

标签： python string python-re

【解决方案1】：

可能不需要正则表达式。只需检查字符串是否存在。

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']
for l in links:
    print(f'{l} contains {[x for x in grids if x.lower() in l.lower().split("-")]}')

输出

north-northeast contains ['north', 'noRtheast']
north-south contains ['north', 'soUth']

【讨论】：

嘿，谢谢，伙计，这是一个非常干净的方法。

【解决方案2】：

当常规 Exp 找不到任何内容时，您的代码打印结果也会出现。您可以添加一些if 检查数组是否为空

import re

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        result = re.findall('\\b' + search + '\\b', text, flags=re.IGNORECASE)
        if len(result):
            print(result)

【讨论】：

是的，这可能是这个逻辑。谢谢

【解决方案3】：

我不知道图书馆“re”，但我想我可以像这样解决你的问题：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        if search.lower() in text.lower():
            print('find '+search+' in '+text+' !')

字符串上的 .lower() 方法会将所有基于大小写的字符小写，如果字符串 search 在字符串 text 中，运算符 in 将返回 true。

【讨论】：

好吧，这种方法的唯一问题是它还会从“链接”中打印“东”，而实际上并不存在。这个方法我试过了。

【解决方案4】：

好吧，我有误会，你可以在比较之前拆分链：

grids = ['north', 'eaSt', 'West','noRtheast', 'soUth']
links = ['north-northeast', 'north-south']

for search in grids:
    for text in links:
        for text_split in text.split('-'):
            if search.lower() == text_split.lower():
                print('find '+search+' in '+text+' !')

输出：

find north in north-northeast !
find north in north-south !
find noRtheast in north-northeast !
find soUth in north-south !

【讨论】：