【发布时间】:2016-11-05 09:34:34
【问题描述】:
当用户在未选择单选选项的情况下提交并且它不起作用时,我试图引发错误。当我呈现这样的字段时:{{ render_field(form.example) }} 它会打印(self.gettext('PICK SOMETHING'),但是当我使用下面的格式时没有任何反应:
{% for subfield in form.religion %}
{{ render_field(subfield, class_="foo") }}
{{ render_field(subfield.label) }}
{% endfor %}
radio.py
class ReligionField(SelectField):
widget = ListWidget(prefix_label=False)
option_widget = RadioInput()
def pre_validate(self, form):
for v, _ in self.choices:
if self.data == v:
break
else:
raise ValueError(self.gettext('PICK SOMETHING'))
class ReligionForm(FlaskForm):
religions = ['Christian', 'Muslim', 'Hindu', 'Buddhist']
choices = [(x.lower(), x.title()) for x in sorted(religions)]
religion = ReligionField('Religion', validators=[DataRequired()], choices=choices, render_kw={"class":"post", "type":"radio"})
@app.route('/',methods=['post','get'])
def hello_world():
form = ReligionForm()
if form.validate_on_submit():
print form.religion.data
else:
print form.errors
return render_template('radio.html', form=form)
如果我在未选择任何选项的情况下提交,如何覆盖 pre_validate 以引发错误?
【问题讨论】:
标签: python flask wtforms flask-wtforms