【发布时间】:2017-04-10 20:39:02
【问题描述】:
我正在尝试在 Department 和 Ticket 表之间创建一对一的关系。这样,在查看 Flask-Admin 内部时,用户将能够看到 Department 名称而不是 ID。
我尝试如下设置关系:
# Ticket Table
class Tickets(db.Model):
__tablename__ = 'tickets'
ticketID = db.Column(db.Integer, nullable=False, primary_key=True, autoincrement=True, unique=True)
cust_name = db.Column(db.String(50), nullable=False)
cust_email = db.Column(db.String(50), nullable=False)
cust_phone = db.Column(db.Integer, nullable=False)
tix_dept = db.Column(db.Integer, db.ForeignKey('department.deptID'))
tix_severity = db.Column(db.Integer, nullable=False)
tix_msg = db.Column(db.String(500), nullable=False)
tix_status = db.Column(db.String(10), nullable=False)
tix_recv_date = db.Column(db.String(20), nullable=False)
tix_recv_time = db.Column(db.Integer, nullable=False)
# define relationship
department = db.relationship('Departments')
# Department Table
class Departments(db.Model):
__tablename__ = 'department'
deptID = db.Column(db.Integer, primary_key=True, autoincrement=True, unique=True)
dept_name = db.Column(db.String(40), nullable=False)
dept_empl = db.Column(db.String(40), nullable=False)
dept_empl_phone = db.Column(db.Integer, nullable=False)
那么我的Flask-Admin 意见是:
admin.add_view(TicketAdminView(Tickets, db.session, menu_icon_type='glyph', menu_icon_value='glyphicon-home'))
admin.add_view(DepartmentAdminView(Departments, db.session))
工单管理面板:
如何显示Department 名称而不是内存位置?
【问题讨论】:
-
department = db.relationship('Departments', backref=backref("tickets", uselist=False))uselist=False 也可以解决您的视图问题
标签: python python-3.x flask flask-sqlalchemy flask-admin