在 Python 中访问 Jquery 键/值

Question

我有一个简单的表单，我需要访问表单的 jquery 代码的键/值和属性。此外，当我尝试使用 request.form['stripeToken'] 在我的视图中创建客户时，它会给出问题末尾提到的错误。我需要使用键/值属性访问 Jquery 脚本中的以下字段：

$("#stripeToken").val(token.id);
$("#stripeEmail").val(token.email);

以下是代码：

jQuery 代码：

<form id="myForm" action="/yearly" method="POST">

<input type="hidden" id="stripeToken" name="stripeToken" />
<input type="hidden" id="stripeEmail" name="stripeEmail" />
<button id="customButton">Purchase</button>
</form>

<script type="text/javascript">
var handler = StripeCheckout.configure({
key: 'pk_test_YgHVTCLIMQLW4NV6ntnJPAXs',
image: 'https://stripe.com/img/documentation/checkout/marketplace.png',
locale: 'auto',
token: function (token) {

$("#stripeToken").val(token.id);
$("#stripeEmail").val(token.email);
$("#myForm").submit();
                    }
                });

$('#customButton12').on('click', function (e) {
      handler.open({
      name: 'Yearly',
      description: 'Yearly Charge',                            
      amount: 9500
                    });
                    e.preventDefault();
                });
          $(window).on('popstate', function () {
                    handler.close();
                });

                </script>

以下是视图：

@app.route('/yearly', methods=['GET', 'POST'])
def yearly_charge():


    key = stripe_keys['publishable_key']
    data = get_profile_data(session['auth_token'])       
    profile_data = data['Student']
    student_id = profile_data.id
    student = get_profile_data(session['auth_token'])['StudentProfile']    
    pkg = Package.query.filter_by(student_id=profile_data.id).first()
    # customer
    stripe_token = request.form['stripeToken']
    email = request.form['stripeEmail']
    if not pkg:

        try:
            customer = stripe.Customer.create(
                email=email,
                source=request.form['stripeToken']

            )
            print request.form
            subscription = stripe.Subscription.create(
                customer=customer.id,
                plan="yearly",
            )
            student_id = profile_data.id
            student.stripe_customer_id = customer.id
            student.stripe_subscription_id = subscription.id
            package = Package(
                student_id=student_id,
                stripe_id = customer.id,
                student_email=request.form['stripeEmail'],
                is_active=True,
                package_type='yearly',
                subscription_id=subscription.id
            )
            dbase.session.add(package)

            dbase.session.commit()

        except stripe.error.CardError as e:
            # The card has been declined
            body = e.json_body
            err = body['error']
        flash("You've successfylly subscribed for annual package.")

    return redirect(url_for('new_template', key=key))

错误：

stripe.error.InvalidRequestError
InvalidRequestError: Request req_AMbjoYEtQR1d6Y: Invalid source object: must be a dictionary or a non-empty string. See API docs at https://stripe.com/docs'

Answer 1

您似乎正在尝试为条纹实现自定义按钮。如果您不知道如何在 python 和 js 之间进行通信，有一种简单的方法可以代替编写所有代码。

<form action='/yoururl' method='post'>
<script src="https://checkout.stripe.com/checkout.js" class="stripe-button"
               data-key="{{ key }}"
               data-description="Your Description"
               data-amount="500"
               data-locale="auto"></script>
               <input type="submit" value='Subscribe' class='btn' style='height:33px;width:50%;color:white;'>
               </form>
               <script>
document.getElementsByClassName("stripe-button-el")[0].style.display = 'none';
               </script>

代码中实际发生的事情是它隐藏了默认的条纹按钮。因此，任何输入按钮都将在标签内为您工作。您可以使用多个按钮，例如，如果您有另一个按钮，您可以使用不同的价格或其他变量，只需更改脚本如下：

 <script>
document.getElementsByClassName("stripe-button-el")[1].style.display = 'none';
               </script>     

如果有第三个按钮，你可以这样做：

        <script>
document.getElementsByClassName("stripe-button-el")[2].style.display = 'none';
               </script>