如何按单词“by”拆分字典并仅保留书名？答案

【问题标题】：How can I split my dictionary by the word 'by' and keep only the book name?如何按单词“by”拆分字典并仅保留书名？
【发布时间】：2020-04-14 02:11:47
【问题描述】：

这是我的字典示例：

{'Fiction Books 2019': ['The Testaments by Margaret Atwood',
'Normal People by Sally Rooney',
'Where the Forest Meets the Stars by Glendy Vanderah',
'Ask Again, Yes by Mary Beth Keane',
'Queenie by Candice Carty-Williams',
"On Earth We're Briefly Gorgeous by Ocean Vuong",
'A Woman Is No Man by Etaf Rum',
'The Overdue Life of Amy Byler by Kelly Harms'... etc }

如何只保留书名？

我尝试了以下方法，但循环将所有书籍添加到字典中的每个键中：

books_name_dict = dict.fromkeys((col_names), [])

for k in books_name_dict:
    for i in range(len(nominee_list_dict_try[k])):
        books_name_dict[k].append(nominee_list_dict_try[k][i].split(' by ')[0])

【问题讨论】：

df['Fiction Books 2019'].str.split(" by ").str[0]?

标签： python dictionary data-science data-analysis

【解决方案1】：

你可以使用：

books = {k: [x.split(" by ")[0] for x in v] for k, v in books.items()}

Demo

【讨论】：

这很好用 - 谢谢！推出 Demo 是个好主意！ ~~

【解决方案2】：

这是因为您在对dict.fromkeys 的调用中提供了一个列表实例[]。这就是为什么您可以在每个列表中看到所有内容的原因，它实际上只是一个列表！

您应该能够通过使用defaultdict 为每个键创建一个新的list 来修复。

import collections

books_name_dict = collections.defaultdict(list)
for k in books_name_dict:
    for i in range(len(nominee_list_dict_try[k])):
        books_name_dict[k].append(nominee_list_dict_try[k][i].split(' by ')[0])

更新

顺便说一句，迭代可以更直接一点。

for k, v in books_name_dict.items():
    for title in v:
        books_name_dict[k].append(title.split(' by ')[0])

【讨论】：

谢谢你，这也很好用！感谢您的意见！

【解决方案3】：

books_name_dict = {'Fiction Books 2019': ['The Testaments by Margaret Atwood',
'Normal People by Sally Rooney',
'Where the Forest Meets the Stars by Glendy Vanderah',
'Ask Again, Yes by Mary Beth Keane',
'Queenie by Candice Carty-Williams',
"On Earth We're Briefly Gorgeous by Ocean Vuong",
'A Woman Is No Man by Etaf Rum',
'The Overdue Life of Amy Byler by Kelly Harms']} 

for k,v in books_name_dict.items():
    books_name_dict[k] = [b.split(" by ")[0] for b in v]

【讨论】：