【发布时间】:2017-09-07 08:41:14
【问题描述】:
我正在尝试将自定义字段添加到 ListView 以更详细地描述实体(以便我可以在模板中使用它),但令人惊讶的是找不到直接的方法来做到这一点。如何向列表中的 each 对象添加上下文?
self.object_list 返回整个列表,并且迭代它以添加这个额外的字段感觉违反直觉。
这是代码的简化版本:
class AreaWiseSchoolsView(ListView):
template_name = 'search/area.html'
paginate_by = 15
def get_queryset(self):
qs = School.objects.filter(area__name=self.kwargs['areaname'])
return qs
def get_context_data(self, **kwargs):
school_type_description = ""
context = super(AreaWiseSchoolsView, self).get_context_data(**kwargs)
# need code here to add the custom field to each object in the list
# school = self.something
# if school.area.filter(pk=9).exists():
# school_type_description = "Some description for Area 9"
# elif school.school_type == 'ND':
# school_type_description = "Some description for ND"
# elif school.school_type == 'MA':
# org_type_description = "Some description for MA"
context['school_type_description'] = school_type_description
return context
在模板中,我需要能够做到以下几点:
{% for school in object_list %}
{{school.school_type_description}}
{% endfor %}
另外,是否有更简单的方法来执行上述操作而不是覆盖 get_context_data()?
【问题讨论】:
-
这种事情最好作为 School 模型本身的方法来完成。
标签: django django-views django-class-based-views