如何从多个文件名中提取一个通用名称并删除我不想要的东西

Question

例如，我有 7 个文件名为：

g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt
g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt
g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt
g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt
g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt
g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt
g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt

我想从这些文件中提取一个名字，命名为：

 g18_84pp_2A_MVP_GoodiesT0_MIX.txt

对此有什么想法吗？谢谢。

有没有可能我只能依赖下划线？

例如，将文件名分隔为

"g18_84pp_2A_MVP2", "_", "GoodiesT0-HKJ-DFG" "_", "MIX-CMVP2_Y1000-MIX", ".txt". 

取"g18_84pp_2A_MVP2" 没有编号2，取"GoodiesT0" 取自"GoodiesT0-HKJ-DFG"，先取"MIX" 取自"MIX-CMVP2_Y1000-MIX"，B/C 我有很多文件有不同的名称用于分隔部分，我想要它通用的也好

Answer 1

import re
names = ['g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt',
'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt',
'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt',
'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt',
'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt',
'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt',
'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt']

f = lambda x: re.findall('g18_84pp_2A_MVP(.*?)_GoodiesT0(.*?)_MIX(.*?)\.txt', x)

for x in names:
    print(f(x))

生产

[('1', '-HKJ-DFG', '-CMVP1_Y1000-MIX')]
[('2', '-HKJ-DFG', '-CMVP2_Y1000-MIX')]
[('3', '-HKJ-DFG', '-CMVP3_Y1000-MIX')]
[('4', '-HKJ-DFG', '-CMVP4_Y1000-MIX')]
[('5', '-HKJ-DFG', '-CMVP5_Y1000-MIX')]
[('6', '-HKJ-DFG', '-CMVP6_Y1000-MIX')]
[('7', '-HKJ-DFG', '-CMVP7_Y1000-MIX')]

过滤与此模式不匹配的名称：

names = list(filter(f, names))

由于不清楚您要做什么，这将是一个很好的起点。

更新

问题已更新。以下是您（可能）想要实现的目标：

import re
names = ['g18_84pp_2A_MVP1_GoodiesT0-HKJ-DFG_MIX-CMVP1_Y1000-MIX.txt',
'g18_84pp_2A_MVP2_GoodiesT0-HKJ-DFG_MIX-CMVP2_Y1000-MIX.txt',
'g18_84pp_2A_MVP3_GoodiesT0-HKJ-DFG_MIX-CMVP3_Y1000-MIX.txt',
'g18_84pp_2A_MVP4_GoodiesT0-HKJ-DFG_MIX-CMVP4_Y1000-MIX.txt',
'g18_84pp_2A_MVP5_GoodiesT0-HKJ-DFG_MIX-CMVP5_Y1000-MIX.txt',
'g18_84pp_2A_MVP6_GoodiesT0-HKJ-DFG_MIX-CMVP6_Y1000-MIX.txt',
'g18_84pp_2A_MVP7_GoodiesT0-HKJ-DFG_MIX-CMVP7_Y1000-MIX.txt']

expression = 'g18_84pp_2A_MVP(.*?)_Goodies(.*?)_MIX(.*?)\.txt'
f = lambda x: re.findall(expression, x)
_f = lambda x: len(re.findall(expression, x))==3

for x in names:
    print(f(x))

输出

[('1', 'T0-HKJ-DFG', '-CMVP1_Y1000-MIX')]
[('2', 'T0-HKJ-DFG', '-CMVP2_Y1000-MIX')]
[('3', 'T0-HKJ-DFG', '-CMVP3_Y1000-MIX')]
[('4', 'T0-HKJ-DFG', '-CMVP4_Y1000-MIX')]
[('5', 'T0-HKJ-DFG', '-CMVP5_Y1000-MIX')]
[('6', 'T0-HKJ-DFG', '-CMVP6_Y1000-MIX')]
[('7', 'T0-HKJ-DFG', '-CMVP7_Y1000-MIX')]

如果需要过滤原始列表：

names = list(filter(_f, names))