格式化数据透视表中的交叉表

Question

我有这个查询以按年龄分组的种族

        create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
        insert into test4 values ('Austin',  'African-American', 'male', 21)
        insert into test4 values ('Austin',  'Asian', 'female', 22)
        insert into test4 values ('Austin',  'Caucasian', 'male', 23)
        insert into test4 values ('Austin',  'Hispanic', 'female', 24)
        insert into test4 values ('Austin',  'African-American', 'Unknown', 25)
        insert into test4 values ('Austin',  'Asian', 'male', 26)
        insert into test4 values ('Austin',  'Caucasian', 'female', 27)
        insert into test4 values ('Austin',  'Hispanic', 'Unknown', 28)
        insert into test4 values ('Austin',  'Asian', 'male', 29)
        insert into test4 values ('Austin',  'Caucasian', 'female', 31)
        insert into test4 values ('Dallas',  'Hispanic', 'Unknown', 32)
        insert into test4 values ('Dallas',  'African-American', 'male', 33)
        insert into test4 values ('Dallas',  'Asian', 'female', 34)
        insert into test4 values ('Dallas',  'Caucasian', 'Unknown', 35)
        insert into test4 values ('Dallas',  'Hispanic', 'male', 500)
        insert into test4 values ('Dallas',  'African-American', 'female', 36)
        insert into test4 values ('Dallas',  'Asian', 'Unknown', 37)
        insert into test4 values ('Dallas',  'Caucasian', 'male', 38)
        insert into test4 values ('Dallas',  'Hispanic', 'female', 39)
        insert into test4 values ('Dallas',  'African-American', 'Unknown', 41)
        insert into test4 values ('Houston',  'Asian', 'male', 42)
        insert into test4 values ('Houston',  'Caucasian', 'female', 43)
        insert into test4 values ('Houston',  'Hispanic', 'Unknown', 44)
        insert into test4 values ('Houston',  'African-American', 'male', 45)
        insert into test4 values ('Houston',  'Asian', 'female', 46)
        insert into test4 values ('Houston',  'Caucasian', 'Unknown', 47)
        insert into test4 values ('Houston',  'Hispanic', 'male', 48)
        insert into test4 values ('Houston',  'African-American', 'female', 49)
        insert into test4 values ('Houston',  'Asian', 'Unknown', 51)
        insert into test4 values ('Houston',  'Caucasian', 'male', 52);

        WITH T AS (
        SELECT 
              A.city as city, A.sex as sex,  
              CASE
                    WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                    WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                    WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
               END AS age_range_race
       FROM test4 AS A
       )
       SELECT  *
       FROM T
       PIVOT( COUNT(age_range_race) FOR age_range_race
           IN(
              [20-30_African-American], 
              [20-30_Asian], 
              [20-30_Caucasian], 
              [20-30_Hispanic],
              [31-40_African-American], 
              [31-40_Asian], 
              [31-40_Caucasian], 
              [31-40_Hispanic],
              [41-50_African-American], 
              [41-50_Asian], 
              [41-50_Caucasian], 
              [41-50_Hispanic]
             )
        ) AS P

当我运行它时，我得到了这个

但我需要的是这个，没有年龄范围。

我将把枢轴放在带有自定义标题的 Radgrid 中，该标题将显示年龄范围，因此列标题中不需要它们。这可能吗？ 提前致谢

Answer 1

我不确定您是否希望将年龄范围合并到单个列中，或者是否希望在查询中重复相同的列名。如果您希望它们折叠起来：

http://sqlfiddle.com/#!3/f0ca0/3

    WITH T AS (
    SELECT 
          A.city as city, A.sex as sex,  
          CASE
                WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
           END AS age_range_race
   FROM test4 AS A
   )
   SELECT  
      P.city,
      P.sex,
      [20-30_African-American] + [31-40_African-American] + [41-50_African-American] as [African-American],

      [20-30_Asian] + [31-40_Asian] + [41-50_Asian] as [Asian],

      [20-30_Caucasian] + [31-40_Caucasian] + [41-50_Caucasian] as [Caucasian],

      [20-30_Hispanic] + [31-40_Hispanic] + [41-50_Hispanic] as [Hispanic]
   FROM T
   PIVOT( COUNT(age_range_race) FOR age_range_race
       IN(
          [20-30_African-American], 
          [20-30_Asian], 
          [20-30_Caucasian], 
          [20-30_Hispanic],
          [31-40_African-American], 
          [31-40_Asian], 
          [31-40_Caucasian], 
          [31-40_Hispanic],
          [41-50_African-American], 
          [41-50_Asian], 
          [41-50_Caucasian], 
          [41-50_Hispanic]
         )
    ) AS P

如果您真的希望多次返回相同的列名，我认为您真的很头疼。这是我能提供的最接近的解决方案（虽然它不是一个很好的解决方案，因为它并没有超出你的基本设置）：

http://sqlfiddle.com/#!3/f0ca0/5

    WITH T AS (
    SELECT 
          A.city as city, A.sex as sex,  
          CASE
                WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
           END AS age_range_race
   FROM test4 AS A
   )
   SELECT  
      P.city,
      P.sex,
          [20-30_African-American] as [African-American1], 
          [20-30_Asian] as [Asian1], 
          [20-30_Caucasian] as [Caucasian1], 
          [20-30_Hispanic] as [Hispanic1],
          [31-40_African-American] as [African-American2], 
          [31-40_Asian] as [Asian2], 
          [31-40_Caucasian] as [Caucasian2], 
          [31-40_Hispanic] as [Hispanic2],
          [41-50_African-American] as [African-American3], 
          [41-50_Asian] as [Asian3], 
          [41-50_Caucasian] as [Caucasian3], 
          [41-50_Hispanic] as [Hispanic3]

   FROM T
   PIVOT( COUNT(age_range_race) FOR age_range_race
       IN(
          [20-30_African-American], 
          [20-30_Asian], 
          [20-30_Caucasian], 
          [20-30_Hispanic],
          [31-40_African-American], 
          [31-40_Asian], 
          [31-40_Caucasian], 
          [31-40_Hispanic],
          [41-50_African-American], 
          [41-50_Asian], 
          [41-50_Caucasian], 
          [41-50_Hispanic]
         )
    ) AS P