通过 Pivot 运算符计算 DateDiff 挑战

Question

我正在尝试计算两个不同时间之间的持续时间。这是我的原始查询及其结果：

  SELECT 
      [DJ_NUMBER]
      ,[PROCESSING_ACTION]
      ,[TRANSACTION_QTY]
      ,[MES_MACHINE]
      ,[ACTION]
      ,[ACTION_TIME]
       ,[UNIQUE_ID]
   FROM [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch]
--   where ACTION in ('SetUp Start', 'Run Start','Run End')
    WHERE PROCESSING_ACTION = 'Job Status'
   Order by DJ_NUMBER asc, ACTION_TIME 
[![SourceData][1]][1]

我尝试使用 DateDiff 函数，但遇到了转换问题。我的“运行结束”和“运行开始”是字符串格式：

DATEDIFF(分钟,'运行结束','运行开始') 我需要的是通过 Pivot Operator 获得以下信息： 持续时间 1 = '运行开始' - '设置开始' 持续时间 2 = '运行结束' - '运行开始'

最终输出应该是这样的：

DJ_NUMBER Duration1（分钟） Duration2（分钟） 19483257 0 50 19483258 0 4.00

这是我的数据透视表运算符。这是我的代码：

       SELECT   DJ_NUMBER 
            , 'SetUp Start' as [SetUp]
            ,'Run Start' as [RunStart]
            ,'Run End' as [RunEnd]
--          ,DATEDIFF(Minute,'Run End','Run Start')
   FROM 
   (
        SELECT   DJ_NUMBER,ACTION,ACTION_TIME
        FROM [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch]
   )   As SourceData
   PIVOT
   (
     COUNT( ACTION_TIME)
     FOR  ACTION IN ([SetUp Start], [Run Start],[Run End])
   ) AS PIVOTTABLE
   Order by DJ_NUMBER asc

[![PivotOperaot Code][4]][4]

任何帮助计算数据透视表中的持续时间将不胜感激。

谢谢你..

Answer 1

由于没有人回答我的问题，我自己就能弄清楚。这是任何有兴趣的人的解决方案：

SELECT 
     A.MES_MACHINE AS LineNo
    ,A.DJ_NUMBER
    ,A.ACTION as SetupStarted
    ,A.ACTION_TIME AS SetupStart
    ,B.ACTION as RunStarted
    ,B.ACTION_TIME AS UpTimeStart
    ,C.ACTION as RunEnded
    ,C.ACTION_TIME AS UpTimeEnd
    ,FORMAT(DATEDIFF(SECOND, A.ACTION_TIME, B.ACTION_TIME)/60.0,'##.##') AS Setup
    ,FORMAT(DATEDIFF(SECOND, B.ACTION_TIME, C.ACTION_TIME)/60.0, '##.##') AS UpTime

FROM [StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] A，[StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] B，[StagingDB].[dbo].[AFL_MES2O_Interface_Data_arch] C WHERE (B.DJ_NUMBER = A.DJ_NUMBER AND B.ACTION_TIME > A.ACTION_TIME) 和 (C.DJ_NUMBER = B.DJ_NUMBER AND C.ACTION_TIME > B.ACTION_TIME)