比较循环外的字符串与java中循环外的字符串

Question

我正在编写一个程序，该程序从用户那里获取一个单词，例如“banana”，将单词“b”的第一个字母像 ananab 一样放在末尾，然后检查它是否拼写相同的单词。我已经为此工作了几天，并尝试了几件事，但仍然不确定如何检查用户给出的字符串，其中一个字符串位于 for 循环中。到目前为止，这是我的程序。

public static void main(String[] args) {

    System.out.println("Enter words that can be checked for backward spelling");
    System.out.println("Please enter a word to check");
    Scanner keyboard = new Scanner(System.in);

    String words = keyboard.nextLine();
    String firstLetter = String.valueOf(words.charAt(0));
    String words2 = words.substring(1);
    String otherwords = words2+firstLetter;


    for (int i=otherwords.length()-1; i>=0; i--){
        String newwords=String.valueOf(otherwords.charAt(i));
        boolean match = newwords.equalsIgnoreCase(words);
        if (match){
            System.out.println("This word matches the criteria we are lookin for");}
        }
}
}

Answer 1

public static void main(String []args){

String input = new Scanner(System.in).nextLine();

char addToEnd = input.charAt(0);
String newString = input.substring(1);
newString+=addToEnd;

if(input.equals(newString)){
System.out.println("This is a match");

}

Answer 2

试试这个：

public static void main(String[] args) {

    System.out.println("Enter words that can be checked for backward spelling");
    System.out.println("Please enter a word to check");
    Scanner sc = new Scanner(System.in);
    String word = sc.nextLine();
    StringBuilder sb = new StringBuilder();
    sb.append(word.substring(1));
    sb.append(word.charAt(0));
    System.out.println(sb.toString().equals(word)?"This is a match.":"This is not a match.");
}

Answer 3

System.out.println("Enter words that can be checked for backward spelling");
System.out.println("Please enter a word to check");
Scanner keyboard = new Scanner(System.in);
String word = keyboard.nextLine();
keyboard.close();
String firstLetter = word.substring(0, 1);
String newWord = word.substring(1) + firstLetter;
// reverse the word
String reversedWord = "";
for (int i = 0; i < word.length(); i++) {
    reversedWord = word.substring(i, i + 1) + reversedWord;
}
// check if it matches
if (reversedWord.equalsIgnoreCase(newWord)) {
    System.out.println("This word matches the criteria we are looking for!!!");
}