您如何将列表中的名称与数组中的名称进行比较？

Question

我有一个电影列表，我想与我从 Facebook Graph API 获得的电影数组进行比较。

以下是 API 获取的示例：

{"data": [
  {
     "name": "The Drift Bible",
     "category": "Movie",
     "id": "227431881228",
     "created_time": "2011-02-27T21:41:04+0000"
  },
  {
     "name": "Shooter",
     "category": "Movie",
     "id": "109671005718938",
     "created_time": "2011-02-16T09:18:29+0000"
  }...

我需要比较的列表很大，但这里有一些：

Wall Street, Shooter, Young Guns, Due Date... 

基本上只需将“数据”中的“名称”与电影标题的“我的列表”进行比较。但无法弄清楚语法

类似：

if ($movies->data->name == 'movie titles list') {echo "You like the same movies";}

我发现了这个：

if (in_array('movie titles list', $a)) {echo "You like the same movies";}

任何想法都会帮助我。

谢谢

Answer 1

数据看起来是 JSON 编码的...

试试这样的：(json_decode)

$large_data = '{"data": [
  {
     "name": "The Drift Bible",
     "category": "Movie",
     "id": "227431881228",
     "created_time": "2011-02-27T21:41:04+0000"
  },
  {
     "name": "Shooter",
     "category": "Movie",
     "id": "109671005718938",
     "created_time": "2011-02-16T09:18:29+0000"
  }]}';

$json_to_array = json_decode($large_data, true);
var_dump(json_decode($large_data, true));    

// You should now be able to compare the two array
echo print_r($json_to_array,true);

编辑：

改进@Eric 发布的内容

$large_data = '{"data": [
  {
     "name": "The Drift Bible",
     "category": "Movie",
     "id": "227431881228",
     "created_time": "2011-02-27T21:41:04+0000"
  },
  {
     "name": "Shooter",
     "category": "Movie",
     "id": "109671005718938",
     "created_time": "2011-02-16T09:18:29+0000"
  }]}';

$movie_list = json_decode($large_data, true);
$movieNames = array();
foreach($movie_list as $movies) {
    foreach($movies as $movie) {
        $movieNames[] = $movie['name'];
    }
}

$myMovies = array('Wall Street', 'Shooter', 'Young Guns', 'Due Date');

$common_movies = array_intersect($movieNames, $myMovies);

foreach($common_movies as $common_movie) {
    echo "We like the same movie ".$common_movie."<br />\n";    
}

Answer 2

另一种方法：

<?php
    $json_data = '{"data": [
        {
           "name": "The Drift Bible",
           "category": "Movie",
           "id": "227431881228",
           "created_time": "2011-02-27T21:41:04+0000"
        },
        {
           "name": "Shooter",
           "category": "Movie",
           "id": "109671005718938",
           "created_time": "2011-02-16T09:18:29+0000"
        }
        ]}';

    $array_data = json_decode($json_data, TRUE);

    $compare_list = array(
        'Wall Street',
        'Shooter',
        'Young Guns',
        'Due Date'
    );

    // <Marco Stumper> phpundhtml at web dot de
    function in_array_multi($needle, $haystack) {
        $found = false;
        foreach ($haystack as $value) {
            if ((is_array($value) && in_array_multi($needle, $value)) || $value == $needle) {
                $found = true;
            }
        }
        return $found;
    }

    foreach ($compare_list as $item) {
        echo '<p>' . $item . (in_array_multi($item, $array_data) ? ' DOES ' : ' does NOT ') . 'exist within $array_data</p>' . PHP_EOL;
    }
?>

输出：

<p>Wall Street does NOT exist within $array_data</p>
<p>Shooter DOES exist within $array_data</p>
<p>Young Guns does NOT exist within $array_data</p>
<p>Due Date does NOT exist within $array_data</p>

Answer 3

使用array_intersect(array1, array2, ... arrayN)

$large_data = '{"data": [
    {
        "name": "The Drift Bible",
        "category": "Movie",
        "id": "227431881228",
        "created_time": "2011-02-27T21:41:04+0000"
    },
    {
        "name": "Shooter",
        "category": "Movie",
        "id": "109671005718938",
        "created_time": "2011-02-16T09:18:29+0000"
    }
]}';

$movies = json_decode($large_data, true)['data'];
$movieNames = array();

//Get only the name from the movie list
foreach($movies as $movie) {
    $movieNames[] = $movie['name'];
}

//Intersect with internal list
print_r(array_intersect($movieNames, $myMovies));