比较并删除部分字符串

Question

我有两个字符串说例子

str1 = "The first two have explicit values, but";
str2 = "first two have explicit values, but disabled is empty";

我需要比较两个字符串并取出部分“前两个有明确的值，但是”

我尝试使用“匹配”，但它返回空值。

有没有办法用 javascript 或 jQuery 来完成这个？

Answer 1

您可以对单词和其他字符组合数组使用简单的 for 循环。

var str1 = "The first two have explicit values, but",
  str2 = "first two have explicit values, but disabled is empty";

// split two string by word boundary
var arr1 = str1.split(/\b/),
  arr2 = str2.split(/\b/);

// initialize variable for result
var str = '';

// iterate over the split array
for (var i = 0; i < arr1.length; i++) {
  // check current word includes in the array and check 
  // the combined word is in string, then concate with str
  if (arr2.includes(arr1[i]) && str2.indexOf(str + arr1[i]) > -1)
    str += arr1[i];
  // if string doesn't match and result length is greater
  // than 0 then break the loop
  else if (str.trim())
    break;
}

console.log(str.trim());

Answer 2

在字符串上使用replace：

var match = 'first two have explicit values, but ';
var str1 = 'the first two have explicit values, but';
var str2 = 'first two have explicit values, but disabled is empty';

str1.replace(match, '')
// returns 'the first two have explicit values, but'

str2.replace(match, '')
// returns 'disabled is empty'

请注意，如果字符串中有大写字母，则必须对其进行“规范化”，这就是第一次检查实际上返回原始字符串的原因（因为没有匹配项）。我建议在字符串上使用toLowerCase。