Python - KeyError：'x'答案

【问题标题】：Python - KeyError: 'x'Python - KeyError：'x'
【发布时间】：2017-03-19 01:26:53
【问题描述】：

这是我的 number2text 代码：

num = raw_input "insert an int"
p = len(num) 
if p == 1:
    print numbers[num]
if p == 2:
    print tens[num[0]] + numbers_teeens[num[1]]
if p == 3:
    print numbers_hundreds[num[0]] + tens[num[1]] + numbers_teeens[num[2]]
if p == 4:
print numbers_thousands[num[0]]+ numbers_hundreds[num[1]] + tens[num[2]] + numbers_teeens[num[3]]
if p == 5:
print numbers_ten_thousands[num[0]] + numbers_thousands[num[1]]+ numbers_hundreds[num[2]] + tens[num[3]] + numbers_teeens[num[4]]
if p == 6:
print numbers_hundred_thousands[num[0]] + numbers_ten_thousands[num[1]] + numbers_thousands[num[2]]+ numbers_hundreds[num[3]] + tens[num[4]] + numbers_teeens[num[5]]

这些是我的字典：

numbers = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine'}
tens = {1: 'Ten', 2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'fifty', 6: 'Sixty', 7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
numbers_teens = {1: 'Eleven', 2: 'Twelve', 3: 'Thirteen', 4: 'Fourteen', 5: 'Fifteen', 6: 'Sixteen', 7: 'Seventeen', 8: 'Eighteen', 9: 'Nineteen'}
numbers_teeens = {0 : '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates lists
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + ' Hundred'}) 
    numbers_thousands.update({k: v.title() + ' Thousand and'})  

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + ' Thousand'})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ' Thousand'})

例如，如果我的输入是 32。我收到此错误KeyError: '2'

我看到了其他一些帖子，但它们只是关于KeyError: x（没有''），而那些确实有'' 的帖子只是因为有人忘记在字典中输入x 键.

谢谢！

【问题讨论】：

标签： python python-2.7 dictionary keyerror

【解决方案1】：

请注意，错误消息显示缺少的键是'2'，换句话说，是一个字符串。你有整数作为键，比如2。您可以将键创建为字符串开头，也可以将字符串数据转换为整数以进行查找。

【讨论】：

我输入了num_i = int(num)，但是当我尝试输入34时它告诉我TypeError: 'int' object has no attribute '__getitem__'
那你没有做int(num)，你做了int[num]（我想）。
而且我知道我仍然没有做p ==3之后的所有事情
这不是聊聊您的程序的好地方。如果 num 是 int，则不能使用 num[i]。
我的代码中没有num[i]...我只是问：如何修复TypeError: 'int' object has no attribute '__getitem__'

【解决方案2】：

这是说 KeyError: '2'。我想你搞混了。您的 number2text 代码错误。而不是 'tens[num[0]]' 考虑 'tens[int(str(num)[0])]'

所以如果你把这两个文本放在一起，你会得到：

numbers = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7:           'Seven', 8: 'Eight', 9: 'Nine'}
tens = {1: 'Ten', 2: 'Twenty', 3: 'Thirty', 4: 'Forty', 5: 'fifty', 6: 'Sixty', 7: 'Seventy', 8: 'Eighty', 9: 'Ninety'}
numbers_teens = {1: 'Eleven', 2: 'Twelve', 3: 'Thirteen', 4: 'Fourteen', 5: 'Fifteen', 6: 'Sixteen', 7: 'Seventeen', 8: 'Eighteen', 9: 'Nineteen'}
numbers_teeens = {0 : '', 1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', 15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', 19: 'Nineteen'}
numbers_hundreds = {}
numbers_thousands = {}
numbers_ten_thousands = {}
numbers_teen_thousands = {}
numbers_hundred_thousands = {}

#Creates lists
for k,v in numbers.items():
    numbers_hundreds.update({k: v.title() + ' Hundred'}) 
    numbers_thousands.update({k: v.title() + ' Thousand and'})  

for k1,v1 in tens.items():
    numbers_ten_thousands.update({k1: v1.title()})

for kt,vt in numbers_teens.items():
    numbers_teen_thousands.update({kt: vt.title() + ' Thousand'})

for k2,v2 in numbers_hundreds.items():
    numbers_hundred_thousands.update({k2: v2.title() + ' Thousand'})

num = raw_input "insert an int"
p = len(num) 
if p == 1:
    print int(numbers[int(str(num))]
if p == 2:
    print tens[int(str(int(str(num)))[0])] + numbers_teeens[int(str(num))[1]]
if p == 3:
    print numbers_hundreds[int(str(num))[0]] + tens[int(str(num))[1]] + numbers_teeens[int(str(num))[2]]
if p == 4:
    print numbers_thousands[int(str(num))[0]]+ numbers_hundreds[int(str(num))[1]] + tens[int(str(num))[2]] + numbers_teeens[int(str(num))[3]]
if p == 5:
    print numbers_ten_thousands[int(str(num))[0]] + numbers_thousands[int(str(num))[1]]+ numbers_hundreds[int(str(num))[2]] + tens[int(str(num))[3]] + numbers_teeens[int(str(num))[4]]
if p == 6:
    print numbers_hundred_thousands[int(str(num))[0]] + numbers_ten_thousands[int(str(num))[1]] + numbers_thousands[int(str(num))[2]]+ numbers_hundreds[int(str(num))[3]] + tens[int(str(num))[4]] + numbers_teeens[int(str(num))[5]]

【讨论】：