【发布时间】:2018-12-19 14:10:18
【问题描述】:
我想在 bootstrap 4 modal header 中使用搜索栏,并使用 ajax get 请求在模态正文中显示搜索结果。
请求成功,但我无法在模态中显示结果。
如何在模式中显示请求预览的结果?
控制器:
public function index()
{
....
//MODAL IS A PARTIAL ON THE INDEX PAGE
return view('friends.index',compact('friends','friendRequests'));
}
public function search(Request $request)
{
if ($request->has('name')) {
$name = $request->query('name');
$results = User::where('name','like','%'.$name.'%')->get();
} else {
$results = User::all();
}
//RETURNING THE MODEL PARTIAL,BUT WITH RESULTS
return view('layouts.partials.friends.modal',compact('results'));
}
相关路线:
Route::get('/friends','FriendsController@index')->name('friends');
Route::get('/friends/search','FriendsController@search')
->name('searchFriend');
索引视图:
<div class="container my-5">
<div class="row">
<h4><i class="fas fa-user-friends"> Friends:</i></h4>
</div>
<div class="row">
<button type="button" class="btn btn-outline-success mx-auto btn-lg"
data-toggle="modal" data-target=".add-friends-modal">
Add new <i class="fas fa-user-plus"></i>
</button>
</div>
//MODAL PARTIAL IS INCLUDED HERE
@include('layouts.partials.friends.modal')
<hr>
@include('layouts.partials.friends.friends-list')
模态部分:
<div class="modal fade add-friends-modal" tabindex="-1" role="dialog"
aria-labelledby="friends-modal" aria-hidden="true">
<div class="modal-dialog modal-lg">
<div class="modal-content">
<div class="modal-header ">
<div class="container">
<div class="row">
<div class="col-6 offset-3">
<h5 class="modal-title text-center">Add new friend:</h5>
</div>
<div class="row mx-auto">
<form class="form-inline mt-4 mb-4" action="javascript:search();">
<input class="form-control mr-sm-2" type="search" placeholder="Search" aria-label="Search"
id="search-input">
<button class="btn btn-outline-success my-2 my-sm-0" type="submit">
<i class="fas fa-search"></i>
</button>
</form>
</div>
</div>
</div>
<button type="button" class="close pull-right" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
//RESULTS SHOULD BE DISPLAYED HERE
@if(isset($results) && count($results)>0)
<ul>
@foreach($results as $result)
<li>{{ $result->name }}</li>
@endforeach
</ul>
@endif
</div>
</div>
搜索AJAX.js
function search() {
var userInput = document.getElementById("search-input").value;
var xhttp = new XMLHttpRequest();
xhttp.open('GET','/friends/search?name='+userInput,true);
xhttp.send();
}
【问题讨论】:
-
我没有看到任何处理 ajax 响应的代码。
-
我认为search方法中的代码足以渲染结果,这是我第一次使用ajax。
标签: javascript ajax laravel twitter-bootstrap laravel-blade