Python - 更新元组字符串元素错误

Question

我有一个数据框，其中每一行都是一个元组列表，即：tuple = (word, pos_tag)。在每一行中，我想通过标记更改某些元组的word，然后用标记的单词更新元组。例如：

初始数据框行：

[('This', 'DET'), ('is', 'VERB'), ('an', 'DET'), ('example', 'NOUN'), ('text', 'NOUN'), ('that', 'DET'), ('I', 'PRON'), ('use', 'VERB'), ('in', 'ADP'), ('order', 'NOUN'), ('to', 'PART'), ('get', 'VERB'), ('an', 'DET'), ('answer', 'NOUN')]

更新词：

updated_word : <IN>example</IN>
updated_word  : <TAR>answer</TAR>

期望的输出：

[('This', 'DET'), ('is', 'VERB'), ('an', 'DET'), ('<IN>example</IN>', 'NOUN'), ('text', 'NOUN'), ('that', 'DET'), ('I', 'PRON'), ('use', 'VERB'), ('in', 'ADP'), ('order', 'NOUN'), ('to', 'PART'), ('get', 'VERB'), ('an', 'DET'), ('<TAR>answer</TAR>', 'NOUN')]

但我收到一个错误，TypeError: 'tuple' object is not callable。有人可以帮忙吗？这是代码：

for idx, row in df.iterrows():
    doc = nlp(row['title'])
    pos_tags = [(token.text, token.pos_) for token in doc if not token.pos_ == "PUNCT"]

    for position, tuple in enumerate(pos_tags, start=1):
        word = tuple[0]
        spacy_pos_tag = tuple[1]
        word = re.sub(r'[^\w\s]', '', word)
        for col in cols:
            if position in row[col]:
                word = f'<{col.upper()}>{word}</{col.upper()}>'
            else:
                continue
            tuple = tuple(word, spacy_pos_tag)
            print(tuple)


 >>>>   Traceback (most recent call last):
 >>>>   tuple = tuple(word, spacy_pos_tag)
 >>>>   TypeError: 'tuple' object is not callable

更新问题

我已按照建议将tuple 替换为tuple_，但我仍然无法取回所需的输出，即每行中的元组列表。有人可以帮助如何更新数据框行吗？这是更新的代码：

for idx, row in df.iterrows():
    doc = nlp(row['title'])
    pos_tags = [(token.text, token.pos_) for token in doc if not token.pos_ == "PUNCT"]
    # print(idx, "tokens, pos : ", pos_tags, "\n")

    for position, tuple_ in enumerate(pos_tags, start=1):
        word = tuple_[0]
        spacy_pos_tag = tuple_[1]
        word = re.sub(r'[^\w\s]', '', word)
        for col in cols:
            if position in row[col]:
                word = f'<{col.upper()}>{word}</{col.upper()}>'
            else:
                continue
            tuple_ = (word, spacy_pos_tag)
        pos_tags.append(' '.join(position, tuple_))
    # pos_tags.append(' '.join(tuple_))
    print(idx, "tokens, pos : ", pos_tags, "\n")
    
    
>>>> Traceback (most recent call last):
>>>> pos_tag(df=df_matched)
>>>> pos_tags.append(' '.join(position, tuple_))
>>>> TypeError: join() takes exactly one argument (2 given)

Answer 1

不要使用tuple作为变量名，因为它是一个内置的python类型名。请尝试以下方法：

    for position, tuple_ in enumerate(pos_tags, start=1):
        word = tuple_[0]
        spacy_pos_tag = tuple_[1]
        word = re.sub(r'[^\w\s]', '', word)
        for col in cols:
            if position in row[col]:
                word = f'<{col.upper()}>{word}</{col.upper()}>'
            else:
                continue

            tuple_ = (word, spacy_pos_tag)
            print(tuple_)

Answer 2

不要使用“元组”作为变量名。这是一个类型名称