计算在 Python 中打开的总行数

Question

我想在输出中显示我的文件中所有行号的计数，但它显示当前行号。

def __init__(self,file):
    self.count = 0
    self.line_count = 0

def start(self):
    with open(self.usersfile, 'rt') as f:
        for line in f.readlines():
            if not self.is_alive:break  # when the user presses Ctrl + C, self.is_alive will become False
            username = line.strip().replace('\n', '')
            self.line_count += 1
            self.check_account(username)


def check_account(self,username):
print('{}[+]Trying ({}/{}) -{}{} Username: {} Taken{}'.format(Fore.WHITE, self.count, self.line_count, Fore.RESET, Fore.RED, username, Fore.RESET))

我的程序的输出在这里：

[+]Trying (1/1) - 
[+]Trying (2/2) -
[+]Trying (3/3) -
[+]Trying (4/4) -
[+]Trying (5/5) -
[+]Trying (6/6) -
[+]Trying (7/7) -
[+]Trying (8/8) - 
[+]Trying (9/9) -
[+]Trying (10/10) - 
....

but i want output :
    [+]Trying (1/20) - 
    [+]Trying (2/20) -
    [+]Trying (3/20) -
    [+]Trying (4/20) -
    [+]Trying (5/20) -
    [+]Trying (6/20) -

如何在with open(self.usersfile, 'rt') as f: 中修复它

Answer 1

随着每条已处理的行逐渐增加总行数。

将完整文件读入列表，然后处理该列表。在处理列表时，增加一个计数器，即“当前行数”并将其传递给输出函数。您列表中的len() 是您可以设置为self.line_count 的总行数：

def start(self):
    with open(self.usersfile, 'rt') as f:
         allLines = f.readlines()
    self.line_count = len(allLines)     
    currLine = 0
    for line in allLines:
         currLine += 1
         # do what you need to do, do not increment self.line_count
         self.check_account(username, currLine) # extend your printmethod to take the 
                                                # currLine nrand print that instead 
                                                # of self.count 
# simplified
def check_account(self,username,currLine):
    print ("{} {}/{}".format(username,currLine,self.line_count) )