铸造失败可能与指针有关

Question

场景

场景包含 2 类操作和地点

这两个类的关系如下所述

Operation{
   storedAt : Date
   type -> OperationType (Pointer)
   place -> Places (Pointer)
}

Places {
   title : String
   type -> OperationType (Pointer)
   location -> PFGeoPoint
} 

我会做什么这只是检索用户附近的地方。为此我使用了：

func getNearPlaces(location: CLLocation){
    if location.isZero() {
        return
    }

    var placeQuery = PFQuery(className: "Places")
    println("getNearPlaces location  \(location)")
    placeQuery.whereKey("location", nearGeoPoint: PFGeoPoint(location:location), withinKilometers: 2)
    placeQuery.whereKey("type", equalTo: detailItem.type)
    placeQuery.limit = 15

    placeQuery.findObjectsInBackgroundWithBlock { (objects:[AnyObject]?, error:NSError?) -> Void in
        if error != nil {
            println("error: \(error)")
            return
        }

        println("results: \(objects?.count)")
        if let objs = objects as? [PFObject] {
            println("casting to [PFObject] ok")
        }

        if let objs = objects as? [Places] {
            println("casting to [Places] ok")
                self.places = objs
        }
        self.updateLocationOnMap()
    }
}

其中 detailItem 是 Operations

的子类

现在重点！如果 Operations 类具有 NO 放置指针列，则所有行的类都可以正常工作。

results: Optional(3)
casting to [PFObject] ok
casting to [Places] ok

接下来，我为 detailItem.place 分配了 [Places] 值之一，并继续使用 app.place。一切都很好。

当我再次启动该应用程序并且 detailItem.place 被评估时，这是我的输出：

results: Optional(3)
casting to [PFObject] ok

投射到 [Places] 失败

有人能解释一下为什么吗？它与di parse或swift有关吗？是不是我做错了什么？

我再补充一些细节：

根据 Parse.com Doc 上的定义：

class Places:PFObject,PFSubclassing{

override class func initialize() {
    struct Static {
        static var onceToken : dispatch_once_t = 0;
    }
    dispatch_once(&Static.onceToken) {
        self.registerSubclass()
    }
}

static func parseClassName() -> String {
    return "Places"
}

@NSManaged var title:String
@NSManaged var type:OperationsType
@NSManaged var location:PFGeoPoint

}

在上述从 PFQuery 检索到的对象的输出下方：

[<Places: 0x7fb94dc9e9d0, objectId: yFDNHinajo, localId: (null)> 
{
    location = "<PFGeoPoint: 0x7fb94d587ad0, latitude: 95.497511, longitude: 19.224867>";
    title = tamoilled;
    type = "<OperationsType: 0x7fb94844a2f0, objectId: 2IPOWNo1lM>";
}, 
<Places: 0x7fb94a84b2f0, objectId: zlh3CMVu0t, localId: (null)> 
{
    location = "<PFGeoPoint: 0x7fb94dc63f20, latitude: 95.498064, longitude: 19.226219>";
    title = "new Place";
    type = "<OperationsType: 0x7fb94844a2f0, objectId: 2IPOWNo1lM>";
}, 
<Places: 0x7fb94dc9f8f0, objectId: ymY7SlA3Is, localId: (null)> 
{
    location = "<PFGeoPoint: 0x7fb94dce4e70, latitude: 95.510635, longitude: 19.217392>";
    title = "Agip 2";
   type = "<OperationsType: 0x7fb94844a2f0, objectId: 2IPOWNo1lM>";
}]

解析 iOS sdk 1.7.2、Xcode 6.3.1

关于 didFinishLaunchingWithOptions

ParseCrashReporting.enable();
Parse.enableLocalDatastore()
Parse.setApplicationId("...", clientKey:"...");

更新

我换了

println("results: \(objects?.count)")
if let objs = objects as? [PFObject] {
    println("casting to [PFObjects] ok \(objs)" )
}

与

self.places = []
for result in objects! {
    println("object \(result)")
    if let place  = result as? Places {
        println("place ok")
        self.places.append(place)
    }
}

结果是 detailItem.place 对应的 Places 对象没有被强制转换为 Places，即使它看起来是正确的！ （重点放在第一本字典上。后面没有'place ok'）

object <Places: 0x7ff5a0f64be0, objectId: yFDNHinajo, localId: (null)> {
location = "<PFGeoPoint: 0x7ff5a312c720, latitude: 95.497511, longitude: 19.224867>";
title = tamoilled;
type = "<OperationsType: 0x7ff5a0edd520, objectId: 2IPOWNo1lM>";
}
object <Places: 0x7ff5a0fbcdc0, objectId: zlh3CMVu0t, localId: (null)> {
location = "<PFGeoPoint: 0x7ff5a3121f30, latitude: 95.498064, longitude: 19.226219>";
title = "new Place";
type = "<OperationsType: 0x7ff5a0edd520, objectId: 2IPOWNo1lM>";
}  
place ok
object <Places: 0x7ff5a3724320, objectId: ymY7SlA3Is, localId: (null)> {
location = "<PFGeoPoint: 0x7ff5a31b8450, latitude: 95.510635, longitude: 19.217392>";
title = "Agip 2";
type = "<OperationsType: 0x7ff5a0edd520, objectId: 2IPOWNo1lM>";
}
place ok

更新 2

我尝试在启动应用程序上执行相同的查询。没有错误，演员工作正常 我现在没有更多资源了。我认为这可能是来自 Parse.com 框架的错误。或者在我的场景中我不知道的东西（应该很简单）

Answer 1

已解决

随着新 Parse 的更新，他们建议添加显式

Places.registerSubclass()

之前

Parse.setApplicationId()