【发布时间】：2016-07-11 14:04:43
【问题描述】：
我已向应用程序添加了扩展（根据苹果文档），但意图处理程序类没有响应我的命令。我缺少的不是。请帮助我，我如何将 siri 添加到我的应用程序中。
// reslove
- (void)resolveContactsForStartAudioCall:(INStartAudioCallIntent *)intent
withCompletion:(void (^)(NSArray<INPersonResolutionResult *> *resolutionResults))completion{
NSArray *contacts;
NSArray * contacts1;
INPersonResolutionResult* result = nil;
if (contacts == intent.contacts) {
for (INPerson *contact in contacts) {
contacts1 = [self contactsMatchingName:contact.displayName];
switch (contacts1.count) {
case 1:
result = [contacts objectAtIndex:0];
[INPersonResolutionResult successWithResolvedPerson:[contacts1 objectAtIndex:0]];
break;
case 0:
result = [INPersonResolutionResult unsupported];
break;
default:
result = [ INPersonResolutionResult disambiguationWithPeopleToDisambiguate:contacts1];
break;
}
}
completion(contacts1);
}else{
result = [INPersonResolutionResult needsValue];
}
}
// confirmation method
- (void)confirmStartAudioCall:(INStartAudioCallIntent *)intent
completion:(void (^)(INStartAudioCallIntentResponse *response))completion{
INStartAudioCallIntentResponse *result = nil;
if (![[NSUserDefaults standardUserDefaults]objectForKey:@"isSignedIn"]) {
result = [[INStartAudioCallIntentResponse alloc]initWithCode:INStartAudioCallIntentResponseCodeReady userActivity:nil];
completion(result);
}else{
NSUserActivity *activity = [[NSUserActivity alloc]initWithActivityType:@"reLogin"];
result = [[INStartAudioCallIntentResponse alloc]initWithCode:INStartAudioCallIntentResponseCodeFailure userActivity:activity];
completion(result);
}
}
【问题讨论】：
-
请提供一些代码
-
Apple's Speakerbox 实现了 Siri，但不幸的是它在 Swift 中。将 CoreLocation.framework 添加到应用程序并在 Settings | 中激活它Siri，并使用电话号码对其进行测试，因为它无法识别联系人。