UISearchBar func 与 Firebase 数据库和 swift答案

【问题标题】：UISearchBar func with Firebase Database and swiftUISearchBar func 与 Firebase 数据库和 swift
【发布时间】：2018-03-28 19:48:41
【问题描述】：

 @IBOutlet weak var tableViewhospitalss: UITableView!
@IBOutlet weak var searchBar: UISearchBar!


//list to store all the Hospitals
var hospitalsList = [hospitalsModel]()
var searchActive : Bool = false
var filtered:[String] = []

和功能

func searchBarTextDidBeginEditing(searchBar: UISearchBar) {
    searchActive = true
}

func searchBarTextDidEndEditing(searchBar: UISearchBar) {
    searchActive = false
}

func searchBarCancelButtonClicked(searchBar: UISearchBar) {
    searchActive = false
}

func searchBarSearchButtonClicked(searchBar: UISearchBar) {
    searchActive = false
}

func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {

    filtered = hospitalsList.filter  ({ (text) -> Bool in
        let temp: NSString = text! as NSString
        let range = temp.range(of: searchText, options: NSString.CompareOptions.caseInsensitive)
        return range.location != NSNotFound
    })
    if(filtered.count == 0){
        searchActive = false;
    } else {
        searchActive = true;
    }
    self.tableViewhospitalss.reloadData()
}

enter image description here

任何人有任何建议，请它给我错误无法将类型“[hospitalsModel]”的值分配给类型“[String]”

【问题讨论】：

标签： swift database firebase uisearchbar

【解决方案1】：

问题是您正在尝试过滤并将“hospitalsModel”转换为字符串，因为您过滤的 var 是 [String]，请尝试使用 map 或 filter -> 返回相同的类型。

【讨论】：

我不明白我应该怎么做，你能告诉我吗
更改过滤类型，var过滤：[hostpitalsModel]
我可以将文件以 zip 格式发送给您，您可以帮我编辑它吗？如果可以，请先生
一定要送我到 fenk86@gmail.com

【解决方案2】：

类医院模型：NSObject {

var id: String?
var name: String?
var subName: String?
var number: String?
var location: String?
var content: String?
var img: String?
var ta5sos: String?
var workTime: String?
var location2 : String?
var aamOrTa5sosy : String?
var latitude: Float?
var longtude: Float?


init(id: String?, name: String?, subName: String?, number :String?, location:String?,content: String?, img: String?, ta5sos: String?, workTime: String?, location2 : String?, aamOrTa5sosy : String?, latitude: Float? , longtude: Float?){
    self.id = id
    self.name = name
    self.subName = subName
    self.number = number
    self.location = location
    self.content = content
    self.img = img
    self.ta5sos = ta5sos
    self.workTime = workTime
    self.location2 = location2
    self.aamOrTa5sosy = aamOrTa5sosy
    self.latitude = latitude
    self.longtude = longtude


}

} `

【讨论】：

【解决方案3】：

class HospitalModel: NSObject  {
 var id: String?
 var name: String?
 var subName: String?
 var number: String?
 var location: String?
 var content: String?
 var img: String?
 var ta5sos: String?
 var workTime: String?
 var location2 : String?
 var aamOrTa5sosy : String?
 var latitude: Float?
 var longtude: Float?


 init(id: String?, name: String?, subName: String?, number :String?, location:String?,content: String?, img: String?, ta5sos: String?, workTime: String?, location2 : String?, aamOrTa5sosy : String?, latitude: Float? , longtude: Float?){
    self.id = id
    self.name = name
    self.subName = subName
    self.number = number
    self.location = location
    self.content = content
    self.img = img
    self.ta5sos = ta5sos
    self.workTime = workTime
    self.location2 = location2
    self.aamOrTa5sosy = aamOrTa5sosy
    self.latitude = latitude
    self.longtude = longtude
 }

 class func filterByName(collection: [HospitalModel], text: String) -> [HospitalModel] {
    return collection.filter({ text.lowercased().range(of: $0.name ?? "") != nil  })
 }

 class func filterBySubname(collection: [HospitalModel], text: String) -> [HospitalModel] {
    return collection.filter({ text.lowercased().range(of: $0.subName ?? "") != nil  })
 }
}

【讨论】：