【发布时间】:2015-05-26 20:15:24
【问题描述】:
我正在尝试在MKMapSnapshotter 中绘制MKCircleRenderer。
所以我需要:
所以我有什么:
我的代码:
+ (void)renderMapRegion:(MKCoordinateRegion)region
withSize:(CGSize)size
annotation:(MKAnnotationView *)annotation
circleRenderer:(MKCircleRenderer *)circleRenderer
completion:(CMMapViewRendererCallback)block
{
MKMapSnapshotOptions *options = [MKMapSnapshotOptions new];
options.region = region;
options.scale = [UIScreen mainScreen].scale;
options.size = size;
MKMapSnapshotter *snapshotter = [[MKMapSnapshotter alloc] initWithOptions:options];
[snapshotter startWithQueue:dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0)
completionHandler:^(MKMapSnapshot *snapshot, NSError *error) {
if (error) {
block(nil, error);
return;
}
UIImage *image = snapshot.image;
UIGraphicsBeginImageContextWithOptions(image.size, YES, image.scale);
{
[image drawAtPoint:CGPointMake(0.0f, 0.0f)];
CGContextRef c = UIGraphicsGetCurrentContext();
if (circleRenderer.path) {
[circleRenderer applyFillPropertiesToContext:c atZoomScale:[UIScreen mainScreen].scale];
CGContextAddPath(c, circleRenderer.path);
CGContextFillPath(c);
}
CGRect rect = CGRectMake(0.0f, 0.0f, image.size.width, image.size.height);
CGPoint point = [snapshot pointForCoordinate:annotation.annotation.coordinate];
if (CGRectContainsPoint(rect, point)) {
point.x = point.x + annotation.centerOffset.x - (annotation.bounds.size.width / 2.0f);
point.y = point.y + annotation.centerOffset.y - (annotation.bounds.size.height / 2.0f);
[annotation.image drawAtPoint:point];
}
UIImage *compositeImage = UIGraphicsGetImageFromCurrentImageContext();
block(compositeImage,nil);
}
UIGraphicsEndImageContext();
}];
}
我的注释是正确的,但是MKCircleRenderer 绘制的坐标有误。
更新 1
经过一番尝试。我只有一个问题:正确的半径大小。我的圈子有 15 米的半径值。但是当我在地图上打印时有一个 119(我不知道单位)
private func renderMap(#placemark: CLPlacemark?, annotationView: MKAnnotationView) {
self.tempPlaceMark = placemark
let region = MKCoordinateRegionMakeWithDistance(annotationView.annotation.coordinate, 5000, 5000)
let circle = MKCircle(centerCoordinate: annotationView.annotation.coordinate, radius: radius!)
var render = MKCircleRenderer(circle: circle)
render.fillColor = Color.YellowColor
CMMapViewRenderer.renderMapRegion(region, withSize: self.mapView.frame.size, annotation: annotationView, circleRenderer: render) { (image: UIImage!, error: NSError!) -> Void in
dispatch_async(dispatch_get_main_queue()) {
if error == nil {
self.tempCoordinate = annotationView.annotation.coordinate
self.tempSnapshotImage = image
}
self.dismissProgress()
}
}
}
基于此解决方案:https://stackoverflow.com/a/8288467/846780
CGPoint circlePoint = [snapshot pointForCoordinate:annotation.annotation.coordinate];
CGRect boundingRect = [circleRenderer rectForMapRect:circleRenderer.circle.boundingMapRect];
CGFloat radius = boundingRect.size.width / 2;
CGContextSetStrokeColorWithColor(c, circleRenderer.fillColor.CGColor);
CGContextSetFillColorWithColor(c, circleRenderer.fillColor.CGColor);
CGContextSetLineWidth(c, 1);
CGContextSetShouldAntialias(c, YES);
CGContextAddArc(c, circlePoint.x, circlePoint.y, radius, 0, 2 * M_PI, true);
CGContextDrawPath(c, kCGPathFill);
【问题讨论】:
-
您的
circleRenderer似乎是使用地图坐标绘制的,并未转换为快照的点坐标。 -
我认为是这样,但是如何在特定位置绘制circleRenderer?
-
您可以将您的圆圈捕获为新图像(上下文)并使用点坐标放置它。
-
顺便说一句,与其把你的工作解决方案放在你的问题中,你可能会post your own answer to your question,这看起来很奇怪。
标签: ios objective-c iphone core-graphics