【发布时间】:2019-05-04 23:23:13
【问题描述】:
我试图重写一个没有使用select 或WaitGroup 的工作程序,以便它可以实现select 和WaitGroup,但我遇到了一个问题,我可以找不到解决办法。看来goroutine死锁了,因为Manager函数没有从writer通道取数据,所以通道被阻塞发送/接收,程序被锁住了。
原来工作的Manager函数,没有select:
func Manager(list *[]Request, writerChan <-chan int) {
ageIn, writersOpen := <-writerChan
for {
if writersOpen { // if writers channel is open
Add(list, Request{Value: ageIn, Count: 1}) // putting new object to list
ageIn, writersOpen = <-writerChan // receiving new player from writer channe;
} else {
break
}
}
}
所以我有一个工作程序,但需要实现WaitGroup 和select,有更新的代码:
更新了Manager 函数,实现select:
func Manager(list *[]Request, writerChan <-chan int) {
defer waitGroup.Done()
for {
select {
case ageIn := <-writerChan:
Add(list, Request{Value: ageIn, Count: 1}) // add player to list
default:
break
}
}
}
更新了Main 函数,实现WaitGroup:
var waitGroup sync.WaitGroup
func main() {
list := ParallelList{List: make([]Request, 0)}
readers, teams, players := ReadData("data.txt")
writerChan := make(chan int) //any2one writers channel
writerFinishChan := make(chan int, 6) // channel to know when all writers are done writing
waitGroup.Add(6)
for i := 0; i < len(teams); i++ {
go Writer(teams, teams[i], writerChan, writerFinishChan)
}
go Manager(&list.List, writerChan)
waitGroup.Wait()
}
Writer 函数向 writerChan 发送数据
func Writer(teams [][]Player, team []Player, writerChan chan<- int,
writerFinishChan chan int) {
defer waitGroup.Done()
count := len(team)
for i := 0; i < count; i++ {
writerChan <- team[i].Age
}
writerFinishChan <- 1 // when writer finishes writing, he puts 1 to the "writerFinishChan"
if len(writerFinishChan) == len(teams) { // if all writers are done writing (the len should be equal to 6)
close(writerChan)
}
}
所以现在的问题是,在实现select 和WaitGroup 之后,我的程序不再正常工作,它给了我一个“致命错误:goroutines 睡着了,死锁”。
也许有人可以帮我解决这个问题?我很确定问题出在Manager 函数中,它是select 块
【问题讨论】:
-
没有办法退出
Managerfor 循环。您在默认情况下放置了break,但select的行为与switch相同,因此它只是打破了默认情况,而不是 for 循环。 -
我想过给循环贴一个标签,f.e.
Loop : for { .. }然后将break Loop放在默认情况下,但我不确定这是解决此问题的正确方法。 -
@Dariuha:虽然这里还有其他问题,但如果您将代码构造为使用早期的
return,那么打破嵌套块通常是最容易的。
标签: go select deadlock channel goroutine