如何合并具有相同名称 SQL Pivot 的行

Question

我正在尝试对 SQL Server 中的一些数据进行非规范化，并且能够成功地对引用表进行透视，但希望能够合并类似的行。

枢轴执行如下

select distinct 
'name' = sFname + ' ' + sLname,
advanced, 
basic, 
standard

from
(select * from dbName..person where deleteFlag <> 'Y') as tableTemp
pivot (
  count(serviceType)
  for serviceType IN (advanced, basic, standard)
) as tablePivot

然后返回

name      | advanced | basic | standard
----------+----------+-------+---------
abby a    |     1    |   0   |    0
abby a    |     0    |   1   |    0
charlie c |     0    |   1   |    0
charlie c |     0    |   0   |    1

但我想以这种形式返回

name      | advanced | basic | standard
----------+----------+-------+---------
abby a    |     1    |   1   |    0
charlie c |     0    |   1   |    1

原始数据的结构类似于

sFname   | sLname   | serviceType |
---------+----------+-------------+
abby     |     a    |   advanced  |
abby     |     a    |   basic     |
charlie  |     c    |   basic     |
charlie  |     c    |   standard  |

如何运行 group by 或 select distinct 之类的操作以在 SQL Server 中返回合并的透视表？

Answer 1

您需要限制子查询中 PIVOT 之前的列。

SELECT [name], 
       [advanced], 
       [basic], 
       [standard]
FROM   (
           SELECT 'name' = sFname + ' ' + sLname, 
                  serviceType
           FROM   person
           WHERE  deleteFlag <> 'Y'
       ) AS tableTemp 
PIVOT(COUNT(serviceType) FOR serviceType IN(advanced, basic, standard)) AS tablePivot;