在 SQLServer 中为该时间段内的付款添加 30 天、60 天和 90 天列答案

【问题标题】：Adding 30 days, 60 days and 90 days column for payments made during that time in SQLServer在 SQLServer 中为该时间段内的付款添加 30 天、60 天和 90 天列
【发布时间】：2020-04-15 11:58:42
【问题描述】：

我想向我的 GridControl 添加三列，显示过去 30、60 和 90 天的付款。下面是我用来获取单个客户的所有付款（金额）的 SQL 语句。

SELECT p.CustomerID, c.FirstName, c.LastName, SUM(p.Amount) As 'Amount
FROM Payment p
INNER JOIN Customer c
on p.CustomerID = c.ID
Group by p.CustomerID, c.FirstName, c.LastName

我也尝试了以下方法，但它只给了我一个 NULL 值

SELECT p.CustomerID, c.FirstName, c.LastName, SUM(p.Amount) As 'Amount', a.[30Days] As '30 Days'
FROM Payment p
inner join Customer c
on p.CustomerID = c.ID
JOIN (SELECT SUM(p.Amount) AS '30Days'
      FROM Payment p 
      WHERE DATEDIFF(day, GETDATE(), PaymentDate) BETWEEN 0 AND 30) AS a ON c.ID = p.CustomerID
Group by p.CustomerID, c.FirstName, c.LastName, a.[30Days]

【问题讨论】：

你有可以用来计算天数的列吗？
您需要添加一列来记录付款完成的日期和时间。这样您就可以使用日期差异来获得您想要的结果。

标签： sql-server vb.net

【解决方案1】：

您应该查看 datediff - 您的参数设置错误，您可以使用条件聚合，因此不需要第三次连接。

SELECT p.CustomerID,  SUM(p.Amount) As 'Amount',
         sum(case when DATEDIFF(day,  PaymentDate,GETDATE()) BETWEEN 0 AND 30 then amount else 0 end) [30days],
         sum(case when DATEDIFF(day,  PaymentDate,GETDATE()) BETWEEN 0 AND 60 then amount else 0 end) [60days],
         sum(case when DATEDIFF(day,  PaymentDate,GETDATE()) BETWEEN 0 AND 90 then amount else 0 end) [90days]
FROM Payment p
INNER JOIN Customer c
on p.CustomerID = c.customerID
Group by p.CustomerID;

【讨论】：