如果已存在则插入或更新

Question

merge into bonuses 
using( select * from bonuses)s ON s.employee_id = '111'   
WHEN MATCHED THEN update set bonus='555' 
WHEN NOT MATCHED THEN insert insert into BONUSES (employee_id) values(115)

Table 的插入查询是

insert into BONUSES (employee_id) values(111)
insert into BONUSES (employee_id) values(112)
insert into BONUSES (employee_id) values(113)
insert into BONUSES (employee_id) values(114)
insert into BONUSES (employee_id) values(115)

如果employee_id=111 已经存在，它应该更新else 它应该插入。 如果有人知道，请提供帮助

Answer 1

类似：

MERGE INTO bonuses dst
USING ( SELECT '111' AS employee_id, '555' AS bonus FROM DUAL ) src
ON ( dst.employee_id = src.employee_id )
WHEN MATCHED THEN
  UPDATE SET bonus = src.bonus
WHEN NOT MATCHED THEN
  INSERT ( employee_id, bonus )
  VALUES ( src.employee_id, src.bonus );

Answer 2

您的语句有两个语法错误。

• 您重复了insert 关键字。
• 您错过了on 子句条件周围的括号。这些是强制性的，与普通 from 子句中的连接条件不同。

所以你的代码应该是这样的：

merge into bonuses b
using( select * from bonuses) s 
ON (s.employee_id = 115)  
WHEN MATCHED THEN update set bonus='555' 
WHEN NOT MATCHED THEN insert(employee_id) values(115)
/

但是，将目标表放在using 子句中是没有意义的。它不会产生你认为它会产生的结果......

SQL> select * from bonuses;

EMPLOYEE_ID      BONUS
----------- ----------
        111
        112
        113
        114
        115

5 rows selected.

SQL> merge into bonuses b
  2  using( select * from bonuses) s 
  3  ON (s.employee_id = 115)
  4  WHEN MATCHED THEN update set bonus='555' 
  5  WHEN NOT MATCHED THEN insert (employee_id) values(115)
  6  /  

9 rows merged.

SQL> select * from bonuses;

EMPLOYEE_ID      BONUS
----------- ----------
        111        555
        112        555
        113        555
        114        555
        115        555
        115
        115
        115
        115

9 rows selected.

SQL> 

也许这样的东西适合你？

merge into bonuses b
using( select * from employees) e 
    ON ( b.employee_id = e.employee_id ) 
WHEN MATCHED THEN 
    update set bonus= 555 
WHEN NOT MATCHED THEN 
    insert (employee_id) values (e.id)

如果您没有与 BONUSES 表不同的员工 ID 来源，您可以使用 DUAL 表来伪造它：

SQL> merge into bonuses b
  2  using( select 115 as employee_id, 555 as bonus from dual union all
  3         select 116 as employee_id, 555 as bonus from dual) e 
  4      ON ( b.employee_id = e.employee_id ) 
  5  WHEN MATCHED THEN 
  6      update set bonus= e.bonus 
  7  WHEN NOT MATCHED THEN 
  8      insert (employee_id) values (e.employee_id) 
  9  /

2 rows merged.

SQL> select * from bonuses;

EMPLOYEE_ID      BONUS
----------- ----------
        111
        112
        113
        114
        115        555
        116

6 rows selected.

SQL> 

Answer 3

我认为你所追求的是：

merge into bonuses tgt
using (select '111' employee_id, '555' bonus from dual) src
  on (tgt.employee_id = src.employee_id)
WHEN MATCHED THEN
  update set tgt.bonus = src.bonus 
WHEN NOT MATCHED THEN
  insert (tgt.employee_id, tgt.bonus)
  values (src.employee_id, src.bonus);

顺便说一句，为什么要将字符串插入通常具有某种形式的 NUMBER 数据类型的列中？这些列是否真的有字符串数据类型（例如 VARCHAR2、CHAR 等）？