使用 COUNT SQL Server 过滤表

Question

我是 SQL 新手。我已经编写了下面的代码，但被 COUNT 函数卡住了。我只想在 Service 表上显示具有 2 个或更多 ServiceID 的 ClientID。我最初尝试在服务表的连接中进行嵌套选择，但收到错误消息。现在使用下面的代码，我收到一个错误

消息 164，第 15 级，状态 1，第 13 行
每个 GROUP BY 表达式必须至少包含一个不是外部引用的列。

我正在努力实现以下目标。谢谢！

client Id	Service ID	Count
1	2	3
1	3	3
1	4	3
2	5	4
2	6	4
2	7	4
2	8	4

SELECT DISTINCT 
    O.OrgName,
    Referral.ClientID, 
    Client.FirstName, 
    Client.LastName, 
    P.ProviderName AS 'School',
    E.ProgramID,
    LI.ListLabel AS 'Reason',
    Race.ListLabel AS 'Race/Ethnicity',
    Gender.ListLabel AS 'Sex/Gender',
    [ServiceId],
    (SELECT COUNT([ServiceID])
     GROUP BY Referral.ClientID
     HAVING COUNT([ServiceID]) >= 2) AS 'Number of Supports'
FROM 
    ProviderReferral Referral
JOIN 
    Provider P ON ReferFromProviderID = P.EntityID
JOIN 
    ProviderReferralExt ON Referral.ProviderReferralID = ProviderReferralExt.ProviderReferralID
INNER JOIN 
    MultiSelectValue MSV ON MSV.ContextID = Referral.ProviderReferralID 
                         AND MSV.ContextTypeID = 87 
                         AND MSV.ListID = 1000001179
INNER JOIN 
    Client ON Referral.ClientID = Client.EntityID
INNER JOIN 
    EnrollmentMember ON client.EntityID = EnrollmentMember.ClientID
INNER JOIN 
    Enrollment E ON EnrollmentMember.EnrollmentID = E.EnrollmentID 
                 AND E.X_CMNonCM = 1
INNER JOIN 
    ListItem LI ON LI.ListValue = MSV.ListValue 
                AND LI.ListID = 1000001179
INNER JOIN 
    ListItem Race ON Race.ListValue = client.Race 
                  AND Race.ListID = 1000000068
INNER JOIN 
    ListItem Gender ON Gender.ListValue = Client.Gender 
                    AND Gender.ListID = 1
INNER JOIN 
    Service ON E.EnrollmentID = Service.EnrollmentID -- the supports table
JOIN 
    Organization O ON o.EntityID = p.OrganizationID
WHERE 
    P.OrganizationID = 33847
    AND E.ProgramID = 1325 
    AND referral.DeletedDate = '9999-12-31' 
    AND o.DeletedDate = '9999-12-31' 
    AND enrollmentmember.DeletedDate = '9999-12-31'
ORDER BY
    referral.ClientID, client.FirstName

Answer 1

您可以使用窗口函数count如下：

Select * from
(Select ...
       ...
       Count([ServiceID]) over (partition by referral.clientid) as cnt
From ...
     ...
) t where cnt > 2;

请注意order by 应该是查询中的最后一个子句。相应地使用它。

根据评论中的请求，将代码添加到您的原始查询中，如下所示：

select * from
(select Referral.ClientID, 
       Client.FirstName, 
       Client.LastName, 
       P.ProviderName as School,
       E.ProgramID,
       LI.ListLabel as Reason,
       Race.ListLabel as "Race/Ethnicity",
       Gender.ListLabel as "Sex/Gender",
       [ServiceId],
       Count([ServiceID]) over (partition by referral.clientid) as cnt -- this -- added open parenthesis before partition
FROM ProviderReferral Referral
    JOIN Provider P on ReferFromProviderID=P.EntityID
    JOIN ProviderReferralExt on Referral.ProviderReferralID=ProviderReferralExt.ProviderReferralID
    INNER JOIN MultiSelectValue MSV on MSV.ContextID = Referral.ProviderReferralID AND 
      MSV.ContextTypeID=87 AND MSV.ListID=1000001179
    INNER JOIN Client on Referral.ClientID=Client.EntityID
    INNER JOIN EnrollmentMember on client.EntityID=EnrollmentMember.ClientID
    INNER JOIN Enrollment E on EnrollmentMember.EnrollmentID=E.EnrollmentID and E.X_CMNonCM=1
    INNER JOIN ListItem LI on LI.ListValue = MSV.ListValue and LI.ListID = 1000001179
    INNER JOIN ListItem Race on Race.ListValue=client.Race and Race.ListID=1000000068
    INNER JOIN ListItem Gender on Gender.ListValue=Client.Gender and Gender.ListID=1
    INNER JOIN Service on E.EnrollmentID=Service.EnrollmentID -- the supports table
    JOIN Organization O on o.EntityID =p.OrganizationID
Where P.OrganizationID=33847
and E.ProgramID=1325 
and referral.DeletedDate = '9999-12-31' and o.DeletedDate='9999-12-31' 
and enrollmentmember.DeletedDate='9999-12-31') t
where cnt > 2 -- this
order by ClientID, FirstName