对您当前的解决方案的几点说明：
- 不要使用“随机”表别名。
D 表示“日期”是有道理的。 y“发票”没有。 d_y_m 也与您的日期格式不匹配。保持表和列别名有意义。
- 不要在整个解决方案中拖拽日期转换。使用
date 类型的日期值，并在最终的select 中转换值一次。
- 不要在一个查询中将开票金额和已付金额的总和分组。如果您在一天内有多个发票或付款，那么总和将不正确！有关说明，请参阅底部的“额外”部分。
- 让我们轻松为您提供帮助。下次，请提供我们可以复制粘贴的示例数据，而不必自己发明。
- 截至 2016 年 4 月 12 日，SQL Server 2005 为 officially unsupported。是时候寻找新版本了！
样本数据
create table Invoices
(
InvoiceDate date,
Total money
);
insert into Invoices (InvoiceDate, Total) values
('2020-11-01', 20),
('2020-11-01', 4),
('2020-11-02', 40),
('2020-11-02', 5),
('2020-11-03', 10),
('2020-11-04', 3),
('2020-11-04', 2);
create table Payments
(
PaymentDate date,
Total money
);
insert into Payments (PaymentDate, Total) values
('2020-11-01', 5),
('2020-11-02', 2),
('2020-11-03', 10),
('2020-11-03', 10),
('2020-11-05', 10);
解决方案
with DateRange as
(
select convert(date, '2020-11-01') as DateValue
union all
select dateadd(day, 1, dr.DateValue)
from DateRange dr
where dr.DateValue < '2020-11-30'
),
InvoicedTotal as
(
select dr.DateValue,
isnull(sum(i.Total), 0) as Invoiced
from DateRange dr
left join Invoices i
on i.InvoiceDate = dr.DateValue
group by dr.DateValue
),
PaidTotal as
(
select dr.DateValue,
isnull(sum(p.Total), 0) as Paid
from DateRange dr
left join Payments p
on p.PaymentDate = dr.DateValue
group by dr.DateValue
)
select convert(varchar(10), dr.DateValue, 102) as [YYYY.MM.DD],
it.Invoiced as [Invoiced],
sum(it.Invoiced) over(order by it.DateValue
rows between unbounded preceding and current row) as [CumInvoiced],
pt.Paid as [Paid],
sum(pt.Paid) over(order by pt.DateValue
rows between unbounded preceding and current row) as [CumPaid],
sum(it.Invoiced) over(order by it.DateValue
rows between unbounded preceding and current row) -
sum(pt.Paid) over(order by pt.DateValue
rows between unbounded preceding and current row) as [RunningTotal]
from DateRange dr
join InvoicedTotal it
on it.DateValue = dr.DateValue
join PaidTotal pt
on pt.DateValue = dr.DateValue
order by dr.DateValue;
结果
仅列出 11 月 30 行中的前 10 行。
YYYY.MM.DD Invoiced CumInvoiced Paid CumPaid RunningTotal
---------- -------- ----------- ------- ------- ------------
2020.11.01 24.0000 24.0000 5.0000 5.0000 19.0000
2020.11.02 45.0000 69.0000 2.0000 7.0000 62.0000
2020.11.03 10.0000 79.0000 20.0000 27.0000 52.0000
2020.11.04 5.0000 84.0000 0.0000 27.0000 57.0000
2020.11.05 0.0000 84.0000 10.0000 37.0000 47.0000
2020.11.06 0.0000 84.0000 0.0000 37.0000 47.0000
2020.11.07 0.0000 84.0000 0.0000 37.0000 47.0000
2020.11.08 0.0000 84.0000 0.0000 37.0000 47.0000
2020.11.09 0.0000 84.0000 0.0000 37.0000 47.0000
2020.11.10 0.0000 84.0000 0.0000 37.0000 47.0000
Fiddle 看看它的实际效果。
额外：为什么不在一个查询中计算两个总数。
使用相同的示例数据，您可以运行此查询来放大特定日期，此处为：2020-11-01。在该日期，样本数据有 2 张发票和 1 笔付款。
with DateRange as
(
select '2020-11-01' as DateValue -- filtering data to explain
)
select dr.DateValue,
isnull(sum(i.Total), 0) as Invoiced,
isnull(sum(p.Total), 0) as Paid
from DateRange dr
left join Invoices i
on i.InvoiceDate = dr.DateValue
left join Payments p
on p.PaymentDate = dr.DateValue
group by dr.DateValue
order by dr.DateValue;
只需执行连接就会得到以下结果。由于合并了left join，因此付款行被列出了两次！
dr.DateValue | i.Total | p.Total
------------ | ------- | -------
2020-11-01 | 20 | 5
2020-11-01 | 4 | 5 --> payment row got joined TWICE
将这些行相加得出当天的付款金额无效。
group by dr.DateValue | sum(i.Total) | sum(p.Total)
--------------------- | ------------ | ------------
2020-11-01 | 24 | 10 --> last sum is WRONG !
编辑：带有cross apply 的SQL Server 2005 版本。但还是建议更新 SQL Server 版本！
with DateRange as
(
select convert(date, '2020-11-01') as DateValue
union all
select dateadd(day, 1, dr.DateValue)
from DateRange dr
where dr.DateValue < '2020-11-30'
),
InvoicedTotal as
(
select dr.DateValue,
isnull(sum(i.Total), 0) as Invoiced
from DateRange dr
left join Invoices i
on i.InvoiceDate = dr.DateValue
group by dr.DateValue
),
PaidTotal as
(
select dr.DateValue,
isnull(sum(p.Total), 0) as Paid
from DateRange dr
left join Payments p
on p.PaymentDate = dr.DateValue
group by dr.DateValue
)
select convert(varchar(10), dr.DateValue, 102) as [YYYY.MM.DD],
it1.Invoiced as [Invoiced],
it3.Invoiced as [CumInvoiced],
pt1.Paid as [Paid],
pt3.Paid as [CumPaid],
it3.Invoiced - pt3.Paid as [RunningTotal]
from DateRange dr
join InvoicedTotal it1
on it1.DateValue = dr.DateValue
join PaidTotal pt1
on pt1.DateValue = dr.DateValue
cross apply ( select sum(it2.Invoiced) as Invoiced
from InvoicedTotal it2
where it2.DateValue <= dr.DateValue ) it3
cross apply ( select sum(pt2.Paid) as Paid
from PaidTotal pt2
where pt2.DateValue <= dr.DateValue ) pt3
order by dr.DateValue;
Updated fiddle.