SQL，在 where 中带有 Like 的大小写

Question

有人可以帮助我吗？ 我有一个具有这种结构的字段：2,3,4,5,6,0,1 他们是星期几，如果今天是一周中的最后一个交货日，我必须找出什么时候，问题是这样的：

例如，今天是第 3 天，通过以下查询，我可以选择所有以数字 3 结尾的人，但如果我有人具有这种​​结构：3,0,1 或 3,1 或 3,0我不明白。

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR)
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast (@today as VARCHAR))

为了解决这个问题，我很难介绍一个案例，所以我的查询将是这个：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR)
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast (@today as VARCHAR))  and  case
        when (@today != 0 or @today!=1) 
        then (cfv.value not like '%,0' or cfv.value not like '%,1')

但在这种情况下，我会收到以下错误消息：

Msg 156, Level 15, State 1, Line 14 关键字附近的语法错误 '不是'。

我确定我犯了一些愚蠢的错误，但我不明白：S

请帮忙！ 非常感谢

Answer 1

使用 CASE 语句应如下所示：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today

select cfv.value
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)

and

CASE
    WHEN (@today !=0 or @today!=1) THEN
        (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
        or cfv.value like '%' + cast (@today as VARCHAR)+',0'
        or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
        or cfv.value like '%' + cast (@today as VARCHAR)+',1')
    ELSE
        (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR))
END = 1

或 *******************************************

 CASE
    WHEN ((@today !=0 or @today!=1) AND (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
        or cfv.value like '%' + cast (@today as VARCHAR)+',0'
        or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
        or cfv.value like '%' + cast (@today as VARCHAR)+',1'))
    THEN 1
    WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1
    ELSE 0
END = 1

但表达式（@today !=0 或 @today!=1）始终为 true。也许你应该找到另一个有意义的条件

Answer 2

您可以将 CASE 语句替换为逻辑表达式：

(((@today != 0 or @today!=1) AND (cfv.value not like '%,0' or cfv.value not like '%,1')) OR NOT (@today != 0 or @today!=1))

所以你的查询会变成：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR) from CompanyFieldvalues cfv
    join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
    where cf.name='NextDeliveryDates' and cfv.companyId in(
        select cfv.companyId
            from CompanyFieldvalues cfv
            join Companies c on c.companyId=cfv.companyId
            where cfv.value='Retailer' and c.status=1) 
            and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value     like '%' + cast (@today as VARCHAR)) 
            and  (((@today != 0 or @today!=1) AND (cfv.value not like '%,0' or cfv.value not like '%,1')) OR NOT (@today != 0 or @today!=1))

Answer 3

帕特里夏更新：

这是我的表，它只有一行的值代表一个人的最后交货日，问题是他们有这样的结构：2,3,4,5,6,0,1

3,0,1
0,1
3,0
5,6
5,5
5
3

我需要知道这个人的最后一个交货日是否是今天（0 和 1 每次都在最后，但实际上它们不是最后一个交货日，而是第一个和第二个交货日）。

我想我必须为 0 和 1 创建 2 个单独的案例，但我没有得到它们：S 这是我实际拥有的：

declare @today int
set @today=DATEPART(dw,GETDATE())-2 /*-2 because the date are managed from a c# code so I need in this way to have the day in the format Monday=0, etc*/
print @today
select cfv.value
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and
 CASE
    WHEN ((@today !=0 or @today!=1) AND (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
    or cfv.value like '%' + cast (@today as VARCHAR)+',0'
    or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
    or cfv.value like '%' + cast (@today as VARCHAR)+',1'))
    then 1
    WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1
    ELSE 0
END = 1

正如你所说，我在第 0 天或第 1 天时每次都有问题。 如果是第 0 天，我必须只选择 value=0，第 1 天我必须选择 value=1 或 value=0,1 的时间，所以我想我需要修改第二个条件：

WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1

创建两个不同的不是吗？

Answer 4

如果我是你并且我很了解你打算做什么，我会按照以下方式实施。我会定义一个分割你的字符串的函数：

create function dbo.SplitString 
(
    @str nvarchar(max), 
    @separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
    select 
        cast(1 as bigint), 
        cast(1 as bigint), 
        charindex(@separator, @str)
    union all
    select
        p + 1, 
        b + 1, 
        charindex(@separator, @str, b + 1)
    from tokens
    where b > 0
)
select
    p-1 ItemIndex,
    substring(
        @str, 
        a, 
        case 
        when b > 0 then b-a 
        ELSE LEN(@str) end) 
    AS Item
from tokens
);

GO

然后我会使用以下条件：

AND where not exists(select * from dbo.SplitString(cfv.value, ',') where    CAST(Item AS INT) > @today )   

我在您提供给我的样品上进行了测试，效果很好。所以对于以下输入：

5 
5 
3,4
5 
5 
5 
3,0,1 
3,0 
5 
3

返回：

3
3,0,1
3,0