动态数据透视表 MS SQL 2008

Question

我正在尝试创建一个动态数据透视表以在不同的列而不是行中获取结果。

这是我用来测试的表

CREATE TABLE [dbo].[Authors](
[Client_Id] [nvarchar](50) NOT NULL,
[Project_Id] [nvarchar](50) NOT NULL,
[Person_Id] [int] NOT NULL,
[Author_Number] [int] NOT NULL,
[Family_Name] [nvarchar](50) NULL,
[First_Name] [nvarchar](50) NULL,
)

INSERT INTO Authors (Client_Id, Project_Id, Person_Id, Author_Number, Family_Name, First_Name)
VALUES ('TEST','TEST',12345,1,'Giust','Fede')
INSERT INTO Authors (Client_Id, Project_Id, Person_Id, Author_Number, Family_Name, First_Name)
VALUES ('TEST','TEST',12345,2,'Giust','Fede')
INSERT INTO Authors (Client_Id, Project_Id, Person_Id, Author_Number, Family_Name, First_Name)
VALUES ('TEST','TEST',12346,1,'Giust','Fede')
INSERT INTO Authors (Client_Id, Project_Id, Person_Id, Author_Number, Family_Name, First_Name)
VALUES ('TEST','TEST',12346,2,'Giust','Fede')
INSERT INTO Authors (Client_Id, Project_Id, Person_Id, Author_Number, Family_Name, First_Name)
VALUES ('TEST','TEST',12346,3,'Giust','Fede')

到目前为止，我得到了这样的结果

CLIENT_ID   PROJECT_ID  PERSON_ID   AUTHOR_NUMBER   FAMILY_NAME FIRST_NAME
TEST        TEST        12345       1               Giust       Fede
TEST        TEST        12345       2               Ma          Ke
TEST        TEST        12346       1               Jones       Peter
TEST        TEST        12346       2               Davies      Bob
TEST        TEST        12346       3               Richards        Craig

我需要这样的结果，并且是动态的，因为有时我可以有 2 个作者或 10 个作者。

CLIENT_ID   PROJECT_ID  PERSON_ID   FAMILY_NAME_1   FIRST_NAME_1    FAMILY_NAME_2   FIRST_NAME_2        FAMILY_NAME_3   FIRST_NAME_3      
TEST        TEST        12345       Giust           Fede            Ma              Ke

TEST        TEST        12346       Jones           Peter           Davies          Bob                 Richards            Craig

我一直在尝试使用此代码，但不断出错

SQL Fiddle

Answer 1

这里有一些解决您问题的建议。

首先，您当前的代码正在取消透视表中的所有列，您只需取消透视Family_Name 和First_Name 列。因此，我不会使用变量来获取此列列表，只需硬编码您需要取消透视的两列。

然后要获取 PIVOT 的列列表，更改代码以同时使用 Author_number 和列名称为 Family_Name 和 First_Name 的字符串：

select @colsPivot = STUFF((SELECT ',' + QUOTENAME(c.col + '_'+cast(Author_Number as varchar(10))) 
                    from Authors
                    cross apply
                    (
                      select 'Family_Name' col, 1 so union all
                      select 'First_Name', 2
                    ) c
                    group by col, author_number, so
                    order by author_number, so
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

这给出了一个列列表：

|                                                                                     COLUMN_0 |
------------------------------------------------------------------------------------------------
| [Family_Name_1],[First_Name_1],[Family_Name_2],[First_Name_2],[Family_Name_3],[First_Name_3] |

对您的代码进行这些更改，最终查询将是

DECLARE @colsPivot AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

select @colsPivot = STUFF((SELECT ',' + QUOTENAME(c.col + '_'+cast(Author_Number as varchar(10))) 
                    from Authors
                    cross apply
                    (
                      select 'Family_Name' col, 1 so union all
                      select 'First_Name', 2
                    ) c
                    group by col, author_number, so
                    order by author_number, so
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')


set @query 
  = 'select Client_id, Project_id, Person_Id, '+@colsPivot+' 
      from
      (
        select Client_id, Project_id, Person_Id, 
          col+''_''+cast(Author_Number as varchar(10)) col, val
        from
        (
          select Client_id, Project_id,
            Person_Id, 
            Author_Number, 
            Family_Name, 
            First_Name
          from Authors
        ) s
        unpivot
        (
          val
          for col in (Family_Name, First_Name)
        ) u
      ) x1
      pivot
      (
        max(val)
        for col in ('+ @colspivot +')
      ) p'

exec(@query)

见SQL Fiddle with Demo。这给出了一个结果：

| CLIENT_ID | PROJECT_ID | PERSON_ID | FAMILY_NAME_1 | FIRST_NAME_1 | FAMILY_NAME_2 | FIRST_NAME_2 | FAMILY_NAME_3 | FIRST_NAME_3 |
-----------------------------------------------------------------------------------------------------------------------------------
|      TEST |       TEST |     12345 |         Giust |         Fede |            Ma |           Ke |        (null) |       (null) |
|      TEST |       TEST |     12346 |         Jones |        Peter |        Davies |          Bob |      Richards |        Craig |