我想创建一个黑名单命令来阻止来自特定公会 discord.py 的邀请

Question

我对这一切都很陌生。我想发出一个命令，阻止用户从黑名单公会发送链接。 该命令如下所示： !blacklist (guild id) 原因 这是目前为止的代码

async def server_blacklist(ctx, guild_id: int,*,reason= "no reason provided"):
    guild = client.get_guild(guild_id)
    invitelink = await delete_invite(guild)

我的第一个想法是我需要以某种方式存储公会 ID（在 .txt 或 .db 中）。但我不知道怎么做。

Answer 1

我之前的回答不满意，所以来一个新的：如果你想写文件，我建议this page。

以及更彻底的解释将某个公会列入黑名单的方法：

我发现可以将某些公会列入黑名单的方法比我想象的要简单得多，邀请对象具有公会属性，因此您可以轻松检查。

一个如何做你想做的事情的“简单”例子是：

@client.command()
async def server_blacklist(ctx, guild_id: int):  # Blacklisting command
    # To add a guild id to the file:
    with open("blacklisted guilds.txt", "a") as blacklistfile:  # Open file in append mode
        blacklistfile.write(f"{guild_id}\n")  # Add a new line with the guild id


@client.event
async def on_message(message):  # Event that triggers every time a message is sent
    if "discord.gg" in message.content:  # Check if message has "discord.gg"
        inviteid = message.content.split("discord.gg/")[1].split(" ")[0]  # Get the invite id from the link
        invite = await client.fetch_invite(inviteid)  # Get the invite object from the id
        guild_id = invite.guild.id  # Get the guild id
        # To retrieve the guild ids and check against another
        with open("blacklisted guilds.txt", "r") as blacklistfile:  # Open file in reading mode
            for idstring in blacklistfile.read().split("\n"):  # Start iterating through all the lines
                if not idstring == "":  # Check if line has content
                    if int(idstring) == guild_id:  # Check if the id from the file is the same as guild_id
                        await message.delete()
                        await message.channel.send(f"{message.author.mention}! Don't send invites to that server here!")
                        break  # Stop the for loop, since we have already matched the guild id to a blacklisted one

    await client.process_commands(message)  # When using the on_message event and commands, remember to add this, so that the commands still work