选择具有相同 ID 的行并选择没有相同 ID 的剩余行

Question

我需要先选择具有公共 ID 的行，然后选择没有公共 ID 的其余行（不重复。）

这是我目前所拥有的：

SELECT DISTINCT a.cars,b.wheels,c.glass
FROM table auto a, tires b, window c
WHERE a.ID = b.ID AND c.ID = a.ID
????AND/OR a.ID <> b.ID????

自动

id cars
1   data
2   data
3   data
4   data

轮胎

id wheels
1   data
2   data
5   data  <-- ID different from table 'Auto' but still want to select it
9   data  <-- ID different from table 'Auto' but still want to select it
200 data  <-- ID different from table 'Auto' but still want to select it

窗口

id glass
1  data
2  data
3  data
4  data

Answer 1

使用 LEFT JOIN，而不是通过 WHERE 子句获得的隐式 INNER JOIN，将从 auto 表中返回匹配和不匹配的行。

SELECT DISTINCT a.cars, b.wheels, c.glass
    FROM auto a
        LEFT JOIN tires b
            ON a.id = b.id
        LEFT JOIN window c
            ON a.id = c.id
    ORDER BY a.cars, b.wheels, c.glass