Discord.js - 如何为数组字符串设置值？

Question

我一直在研究“BlackJack”命令，它是一个迷你游戏。现在，我很确定只需为每个嵌入添加不同的数学生成器就可以了，如果加法方程等于 21，它就告诉你你输了！如果我知道如何为“cards”数组中的每个字符串分配不同的值，我就可以自己完成所有这些工作。

例如... 黑桃 A = 11

然后我就可以使用数学了... randomCard1 + randomCard 2 有点东西

const { CommandoClient, SQLiteProvider, Command } = require('discord.js-commando');
const { RichEmbed } = require('discord.js');

const client = new CommandoClient({
    commandPrefix: 'w!',
    unknownCommandResponse: false,
    owner: ['254323224089853953', '121222156121014272'],
    disableEveryone: true
});

module.exports = class BlackJackCommand extends Command {
    constructor(client) {
        super(client, {
            name: 'blackjack',
            group: 'ping',
            memberName: 'blackjack',
            description: 'Use w!blackjack [bet] to bet on blackjack! Use w!blackjackhelp to find out more!',
            examples: ['w!blackjack 20'],
            args: [
                {
                    key: 'ping',
                    prompt: 'How much ping do you want to bet?',
                    type: 'integer'
                }
            ]
        });    
    }


    async run(message, args) {

        var responses = Array('Stand','Hit','Double Down')
        var cards = Array('Ace of Clubs','2 of Clubs','3 of Clubs','4 of Clubs','5 of Clubs','6 of Clubs','7 of Clubs','8 of Clubs','9 of Clubs','10 of Clubs','Jack of Clubs','Queen of Clubs','King of Clubs','Ace of Diamonds','2 of Diamonds','3 of Diamonds','4 of Diamonds','5 of Diamonds','6 of Diamonds','7 of Diamonds','8 of Diamonds','9 of Diamonds','10 of Diamonds','Jack of Diamonds','Queen of Diamonds','King of Diamonds','Ace of Hearts','2 of Hearts','3 of Hearts','4 of Hearts','5 of Hearts','6 of Hearts','7 of Hearts','8 of Hearts','9 of Hearts','10 of Hearts','Jack of Hearts','Queen of Hearts','King of Hearts','Ace of Spades','2 of Spades','3 of Spades','4 of Spades','5 of Spades','6 of Spades','7 of Spades','8 of Spades','9 of Spades','10 of Spades','Jack of Spades','Queen of Spades','King of Spades');
        var joker = ('<:joker:415835828770570240>')
        const randomCard1 = cards[Math.floor(Math.random()*cards.length)];
        const randomCard2 = cards[Math.floor(Math.random()*cards.length)];

        const randomDealer = responses[Math.floor(Math.random()*responses.length)];


        const initial = new RichEmbed()
        .setTitle(`**${joker} Blackjack! ${joker}**`)
        .setAuthor(message.author.tag, message.author.displayAvatarURL)
        .setThumbnail('https://pbs.twimg.com/profile_images/1874281601/BlackjackIcon.png')
        .addField('**Initial Deal:**', `Your Cards:\n- ${randomCard1}\n- ${randomCard2}`)
        .setColor(0xAE0086)

        const dealer1 = new RichEmbed()
        .setTitle(`**${joker} Blackjack! ${joker}**`)
        .setAuthor(message.author.tag, message.author.displayAvatarURL)
        .setThumbnail('https://pbs.twimg.com/profile_images/1874281601/BlackjackIcon.png')
        .addField('**Initial Deal:**', `Your Cards:\n- ${randomCard1}\n- ${randomCard2}`)
        .addField('**Dealer\'s Turn 1:**', `Choice: ${randomDealer}`)
        .setColor(0xAE0086)

        message.embed(initial);

        const filter = message => message.content.includes('stand');

        message.reply('Your turn to choose: ``stand`` ``hit`` ``surrender`` ``double down`` ``cancel``')
        .then(function(){
            message.channel.awaitMessages(response => filter, {
              max: 1,
              time: 300000000,
              errors: ['time'],
            })
            .then((collected) => {
                message.embed(dealer1);
              })
              .catch(function(){
                message.channel.send('You didnt respond in time!');
              });
          });
      }
    }

Answer 1

您至少可以采取两种方法。我首先要注意的是，您将 ace 视为等于 11，但规则允许 1 或 11。

定位

因为这个数组的内容遵循一个模式，我们可以使用数学来查看数组中的位置并确定卡片的值。如果index 持有我们的数组偏移量，我们可以对其执行以下操作：

• 将数字的模数乘以 13，这会将值从 0 到 12 的花色分开
• 加一，得到每套花色中的数字 1-13
• 取该数字或 10 中的最小值，将面卡变成 10 秒
• 返回并使用该值，如果它是 1，也可能是 11

这可能看起来像：

value = Math.min((index % 13) + 1, 10)

它涵盖了处理 Ace 的两个可能值的最后一步之外的所有步骤。

对象

您可以将定义卡片的方式更改为：

var cards = [
    {value: 1, name: 'Ace of Clubs'},
    {value: 2, name: 'Two of Clubs'},
    {value: 3, name: 'Three of Clubs'}
];

并以cards[index].name 访问卡的名称，以cards[index].value 访问值，其中index 是数组中的偏移量。请注意，该数组仅使用方括号而不是 Array( 声明。