当用户对 2 个反应做出反应时，机器人不会读取第二个反应.. discord.py

Question

我有一个代码，机器人需要读取用户对消息的两种反应，但使用此代码，机器人不会打印“第二次检查”，这意味着机器人不阅读第二次反应和在第一个实现后停止

reacttn = True
def check(reaction, user):
  return user == members.users[members.leader].user and reaction.message.id == ttreact.id
while reacttn == True:
  reaction, user = await client.wait_for("reaction_add", check=check)

  if len(members.users) == 2:
    if str(reaction.emoji) == "1️⃣":
      print("first check")
    if str(reaction.emoji) == "2️⃣":
      print("second check")
    await asyncio.sleep(5)
    reacttn = False

Answer 1

你可以这样做：

from collections.abc import Sequence


def sequence(seq):
   if seq is None:
       return ()
   if isinstance(seq, Sequence) and not isninstance(seq, str):
       return seq
   else:
      return(seq,)

def reaction_check:(message=None, emoji=None, author=None, ignore_bot=True):
    message = sequence(message)
    message = tuple(m.id for m in message)
    emoji = sequence(emoji)
    author = sequence(author)
    def check(reaction, user):
        if ignore_bot and user.bot:
            return False
        if message and reaction.message.id not in message:
            return False
        if emoji and reaction.emoji not in emoji:
            return False
        if author and user not in author:
            return False
        return True
    return check

在命令中：

msg = await ctx.send("react to this message!")

await msg.add_reaction("1️⃣")
await msg.add_reaction("2️⃣")

check = reaction_check(message=msg, author=member, emoji=("1️⃣","2️⃣"))

reaction, user = await client.wait_for("reaction_add", check=check)

if reaction.emoji == "1️⃣":
   #first logic

if reaction.emoji == "2️⃣":
   #second logic