当年与上年之间的出生报告和日期参数

Question

我正在使用 stackoverflow 的一位同事向我建议的以下查询。以下查询使用日期来获取当前年份 (>2016,2015, Here's the code given to me

SELECT grade,
       COUNT( DISTINCT CASE WHEN DATE '2015-01-01' >= date_column
                             AND date_column < DATE '2016-01-01'
                            THEN customer_id END
            ) AS number_of_unique_customers_in_2015,
       COUNT( DISTINCT CASE WHEN DATE '2016-01-01' >= date_column
                             AND date_column < DATE '2017-01-01'
                            THEN customer_id END
            ) AS number_of_unique_customers_in_2016
FROM   Customers
WHERE  Date_Column >= DATE '2015-01-01'
AND    Date_Column <  DATE '2017-01-01'
GROUP BY grade;

谁能在 birt 报告中建议如何做到这一点？

Answer 1

查看my answer here，了解如何在 Birt 中向 SQL 查询添加参数。您应该添加您的报告参数以首先输入用户的日期。

要从输入参数中减去一年，您应该在添加参数的 SQL 查询中使用带有一年负值的 DATEADD。

对于输入参数日期2016-01-01，您的查询应如下所示：

SELECT grade,
       COUNT( DISTINCT CASE WHEN DATEADD(year, -1, ?) >= date_column
                             AND date_column < ?
                            THEN customer_id END
            ) AS number_of_unique_customers_in_last_year,
       COUNT( DISTINCT CASE WHEN ? >= date_column
                             AND date_column < DATEADD(year, 1, ?)
                            THEN customer_id END
            ) AS number_of_unique_customers_in_current_year
FROM   Customers
WHERE  Date_Column >= DATEADD(year, -1, ?)
AND    Date_Column <  DATEADD(year, 1, ?)
GROUP BY grade;