如何重置当月至今的总计

Question

SELECT DISTINCT
    ACCOUNTDATE,
    PROPERTYNAME,
    rt.management
FROM 
    aaa t
CROSS APPLY
    (SELECT 
         SUM(MANAGEMENT) AS management
     FROM
         aaa
     WHERE
         PROPERTYNAME = t.PROPERTYNAME 
         AND ACCOUNTDATE <= t.ACCOUNTDATE) as rt
WHERE 
    AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY 
    AccountDate

这是我的查询，我想计算本月至今的总和， 例如：1/08/2016-31/08/2016 的总和必须从 1/09/2016-31/09/2016 的开头重新设置。

但根据上述查询，我​​无法重置下个月的总计。

Answer 1

如果您想要运行总计，那么在 SQL Server 2012+ 中，您可以使用：

select aaa.*,
       sum(management) over (partition by year(accountdate), month(accountdate)
                             order by accountdate
                            ) as rt
from aaa
where AccountDate between @STARTOFMONTH_MAN and @ENDOFMONTH_MAN
order by Accountdate;

在早期版本中，您可以使用 cross apply 并在逻辑中包含年份和月份：

SELECT t.*, rt.management
from aaa t cross apply     
     (select SUM(MANAGEMENT) as management
      from aaa t2
      where t2.PROPERTYNAME = t.PROPERTYNAME and
            year(t2.accountdate) = year(t.accountdate) and
            month(t2.accountdate) = month(t.accountdate) and
            t2.ACCOUNTDATE <= t.ACCOUNTDATE 
      ) rt
WHERE AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY AccountDate;

Answer 2

如果您不使用 SQL-Server 2012+，则必须使用相关查询（或某种其他联接）：

SELECT DISTINCT t.ACCOUNTDATE
       ,t.PROPERTYNAME
       ,(SELECT SUM(s.MANAGMENT) FROM aaa s
         WHERE MONTH(t.accountdate) = MONTH(s.accountdate)
           AND YEAR(t.accountdate) = YEAR(s.accountdate)
           AND  s.PROPERTYNAME = t.PROPERTYNAME) as rt
from aaa t
WHERE t.AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY t.AccountDate

Answer 3

试试

SELECT DISTINCT
    ACCOUNTDATE
    ,PROPERTYNAME
    ,rt.management
from aaa t
cross apply     
    (select SUM(MANAGEMENT) as management
     from aaa
     where 
     PROPERTYNAME = t.PROPERTYNAME and
     ACCOUNTDATE BETWEEN dateadd(MONTH, datediff(MONTH, 0,t.ACCOUNTDATE),0) -- start of month
AND t.ACCOUNTDATE 
    ) as rt
WHERE AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY AccountDate

Answer 4

SELECT DISTINCT
    ACCOUNTDATE
    ,PROPERTYNAME
    ,rt.management
from aaa t
cross apply     
    (select SUM(MANAGEMENT) as management
     from aaa
     where 
     PROPERTYNAME = t.PROPERTYNAME and
     ACCOUNTDATE BETWEEN dateadd(MONTH, datediff(MONTH, 0,t.ACCOUNTDATE),0) -- start of month
AND t.ACCOUNTDATE 
    ) as rt
WHERE AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY AccountDate

Answer 5

为了始终给出该项目所在月份的累计总数，试试这个 - 它可以避免对之前任何月份的帐户求和

    SELECT DISTINCT
    ACCOUNTDATE,
    PROPERTYNAME,
    rt.management
FROM 
    aaa t
CROSS APPLY
    (SELECT 
         SUM(MANAGEMENT) AS management
     FROM
         aaa
     WHERE
         PROPERTYNAME = t.PROPERTYNAME 
         AND ACCOUNTDATE <= t.ACCOUNTDATE 
         and MONTH(accountdate) = MONTH(t.accountdate) 
         and year(accountdate) = year(t.accountdate)) as rt
WHERE 
    AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY 
    AccountDate

在 4 月开始的财政年度试试这个

    SELECT DISTINCT
    ACCOUNTDATE,
    PROPERTYNAME,
    rt.management,
    fy.managementFinancialYear
FROM 
    aaa t
CROSS APPLY
    (SELECT 
         SUM(MANAGEMENT) AS management
     FROM
         aaa
     WHERE
         PROPERTYNAME = t.PROPERTYNAME 
         AND ACCOUNTDATE <= t.ACCOUNTDATE 
         and MONTH(accountdate) = MONTH(t.accountdate) 
         and year(accountdate) = year(t.accountdate)) as rt
CROSS APPLY
    (SELECT 
         SUM(MANAGEMENT) AS managementFinancialYear
     FROM
         aaa
     WHERE
         PROPERTYNAME = t.PROPERTYNAME 
         AND ACCOUNTDATE <= t.ACCOUNTDATE 
         and (year(accountdate) * 12 + MONTH(accountdate) - 4) % 12  = (year(t.accountdate) * 12 + MONTH(t.accountdate) - 4) % 12 
         )as fy
WHERE 
    AccountDate BETWEEN @STARTOFMONTH_MAN AND @ENDOFMONTH_MAN
ORDER BY 
    AccountDate