缺少对象或列名称或为空。但不是吗？

Question

我正在处理第 7 组查询，所有查询都使用 SELECT * INTO some_table 没有问题。由于某种原因，SQL Server 中的以下查询引发了错误

对象或列名丢失或为空。对于选择进入 语句，验证每一列都有一个名称。对于其他陈述，请查看 对于空别名。不允许使用定义为 "" 或 [] 的别名。 将别名更改为有效名称。

关于它可能是什么的任何想法？ 请注意，在没有 select into 的情况下运行查询将导致数据按预期返回和显示。

Select * into MYDB.MY_TBL
SELECT OT.U_ID AS "U_ID"
    ,R.E AS "E"
    ,R.IR AS "CKT"
    ,A.RI AS "OC"
    ,A.EQ AS "SEQ"
    ,A.HA AS "CHA"
    ,A.A_HA AS "ATE"
    ,A.BIL AS "BIL"
    ,A.CHA AS "CHAA"
    ,A.RAT AS "AMT"
    ,A.PRM AS "PREM"
    ,A.T_CHG AS "RAT"
    ,A.PER AS "LAS"
    ,A.S_BIL AS "BIL_A"
    ,A.CD AS "CDE"
    ,A.CBIL_J AS "BIL_J"
    ,A.AMT_D AS "TB"
    ,A.CRY AS "CTRY"
    ,A.RVW AS "RVW"

FROM MYDB.OTHER_TBL OT
JOIN [LINKEDSERVER\INST,0000].FE.dbo.tblR R
    ON OT.E = R.E
JOIN [LINKEDSERVER\INST,0000].FE.dbo.tblA A
    ON R.IR = A.IR

WHERE OT.U_ID = 'TEST'

Answer 1

您有两个selects。我想你只是想要：

SELECT OT.U_ID AS "U_ID",
       . . .
INTO MYDB.MY_TBL
FROM . . . 

INTO 应该在SELECT 列列表之后。

或者，您可以使用子查询，但这似乎没有必要。

Answer 2

@GordonLinoff 示例的工作原理我意识到我忘记了什么，这是我通常使用的 FROM () 子查询设置。

我将提供一个与 Gordon 方法相反的示例。

IE：

Select * into MYDB.MY_TBL
FROM(
SELECT OT.U_ID AS "U_ID"
    ...
FROM MYDB.OTHER_TBL OT
WHERE OT.U_ID = 'TEST'
) SUB

Answer 3

请注意这两点：

1.您有两列具有给定的“CHA”别名

2.看来您需要将查询重写为：

SELECT OT.U_ID AS "U_ID"
    ,R.E AS "E"
    ,R.IR AS "CKT"
    ,A.RI AS "OC"
    ,A.EQ AS "SEQ"
    ,A.HA AS "CHA_DUPLICATE"
    ,A.A_HA AS "ATE"
    ,A.BIL AS "BIL"
    ,A.CHA AS "CHA_DUPLICATE2"
    ,A.RAT AS "AMT"
    ,A.PRM AS "PREM"
    ,A.T_CHG AS "RAT"
    ,A.PER AS "LAS"
    ,A.S_BIL AS "BIL_A"
    ,A.CD AS "CDE"
    ,A.CBIL_J AS "BIL_J"
    ,A.AMT_D AS "TB"
    ,A.CRY AS "CTRY"
    ,A.RVW AS "RVW"

INTO MYDB.MY_TBL -- <<<<<<< NOTE

FROM MYDB.OTHER_TBL OT
JOIN [LINKEDSERVER\INST,0000].FE.dbo.tblR R
    ON OT.E = R.E
JOIN [LINKEDSERVER\INST,0000].FE.dbo.tblA A
    ON R.IR = A.IR

WHERE OT.U_ID = 'TEST'