【发布时间】:2014-08-02 00:18:16
【问题描述】:
我的程序无法解开我的数据,其中 pickle.load(f) 与 pickle.dump(object,f) 不匹配。 我的问题是以下代码哪里出错了,因为我已经尝试了各种 文件模式与下面我的代码上方列出的相应错误:
f = open(home + '/.GMouseCfg','ab+')
out:它们是不同的
f = open(home + '/.GMouseCfg','ab+', encoding='utf-8')
ValueError:二进制模式不接受编码参数
f = open(home + '/.GMouseCfg','a+')
TypeError: 必须是 str,而不是 bytes
import abc, pprint
from evdev import ecodes as e
from os.path import expanduser
try:
import cPickle as pickle
except:
import pickle
class Command(object):
__metaclass__ = abc.ABCMeta
@abc.abstractmethod
def set(self, data):
"""set data used by individual commands"""
return
@abc.abstractmethod
def run(self):
"""implement own method of executing data of said command"""
return
class KeyCommand(Command):
def __init__(self, data):
self.data = data
def set(data):
self.data = data
def run(self):
pass
def __str__(self):
return data
class SystemCommand(Command):
def __init__(self, data):
self.data = data
def set(data):
self.data = data
def run(self):
pass
def __str__(self):
return data
if __name__ == '__main__':
ids = [2,3,4,5,6,7,8,9,10,11,12]
home = expanduser('~')
f = open(home + '/.GMouseCfg','a+')
f.seek(0)
commands = list()
commands.append(KeyCommand({3:[e.KEY_RIGHTCTRL,e.KEY_P]}))
commands.append(SystemCommand({5:['gedit','./helloworld.txt']}))
pickle.dump(commands,f)
f.seek(0)
commands2 = pickle.load(f)
if commands == commands2:
print('They are the same')
else:
print('They are different')
我已经阅读了大量有关泡菜和文件 io 的 python 文档,但无法辨别为什么我的原始对象和未腌制的对象之间存在差异
【问题讨论】:
标签: python-3.x file-io pickle