需要 kSOAP 编组帮助

Question

有没有人有一个使用 kSOAP 包的复杂对象编组的好例子？

Answer 1

虽然这个例子不是可编译和完整的，但基本思想是有一个类告诉 kSOAP 如何将 XML 标记转换为对象（即 readInstance()）以及如何将对象转换为 XML 标记（即writeInstance())。

public class MarshalBase64File implements Marshal {

  public static Class FILE_CLASS = File.class;

  public Object readInstance(XmlPullParser parser, String namespace, String name, PropertyInfo expected)
      throws IOException, XmlPullParserException {
    return Base64.decode(parser.nextText());
  }

  public void writeInstance(XmlSerializer writer, Object obj) throws IOException {
    File file = (File)obj;
    int total = (int)file.length();
    FileInputStream in = new FileInputStream(file);
    byte b[] = new byte[4096];
    int pos = 0;
    int num = b.length;
    if ((pos + num) > total) {
      num = total - pos;
    }
    int len = in.read(b, 0, num);
    while ((len != -1) && ((pos + len) < total)) {
      writer.text(Base64.encode(b, 0, len, null).toString());
      pos += len;
      if ((pos + num) > total) {
        num = total - pos;
      }
      len = in.read(b, 0, num);
    }
    if (len != -1) {
      writer.text(Base64.encode(b, 0, len, null).toString());
    }
  }

  public void register(SoapSerializationEnvelope cm) {
    cm.addMapping(cm.xsd, "base64Binary", MarshalBase64File.FILE_CLASS, this);
  }
}

稍后，当您调用 SOAP 服务时，您会将对象类型（在本例中为 File 对象）映射到编组类。 SOAP 信封将自动匹配每个参数的对象类型，如果它不是内置类型，则调用关联的编组器将其转换为 XML。

public class MarshalDemo {

  public String storeFile(File file) throws IOException, XmlPullParserException {
    SoapObject soapObj = new SoapObject("http://www.example.com/ws/service/file/1.0", "storeFile");
    soapObj.addProperty("file", file);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    new MarshalBase64File().register(envelope);
    envelope.encodingStyle = SoapEnvelope.ENC;
    envelope.setOutputSoapObject(soapObj);

    HttpTransport ht = new HttpTransport(new URL(server, "/soap/file"));
    ht.call("http://www.example.com/ws/service/file/1.0/storeFile", envelope);

    String retVal = "";
    SoapObject writeResponse = (SoapObject)envelope.bodyIn;
    Object obj = writeResponse.getProperty("statusString");
    if (obj instanceof SoapPrimitive) {
      SoapPrimitive statusString = (SoapPrimitive)obj;
      String content = statusString.toString();
      retVal = content;
    }
    return retVal;
  }
}

在这种情况下，我使用 Base64 编码来编组 File 对象。