Postgresql 存储函数只返回不带列名的值

Question

我是 Postgresql 的新手。我刚刚创建了复合类型的函数。

以下是我的代码：

create type search_type as (
result_id bigint, 
result_name character varying,
result_loc character varying,
result_type character varying,
result_pic character varying
);

    CREATE OR REPLACE FUNCTION search_result("@search_text" character varying)
  RETURNS SETOF search_type AS
$BODY$
DECLARE r search_type%rowtype;
BEGIN   
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') LOOP
        RETURN NEXT r;
    END LOOP;
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' LOOP
        RETURN NEXT r;
    END LOOP;
    RETURN;
END
$BODY$
  LANGUAGE plpgsql

但是当我像下面的代码那样调用存储函数时，它只会得到没有列名的数据。

SELECT search_result('c');

会是什么原因？

如何返回带有值的列名？

以上是返回的记录。

但我需要得到结果：

result_id  result_name  result_loc      result_pic  result_type
---------  -----------  ----------      -----------  ----------
13         test1        San Francisco                user
14         test2        San Francisco                user
15         test3        San Francisco                user
16         test4        San Francisco                user
17         test5        San Francisco                user

我怎样才能得到上面的结果？

更新

新代码：

CREATE OR REPLACE FUNCTION search_result("@search_text" character varying, "@row_start" integer, "@row_end" integer)
  RETURNS SETOF search_type AS
$BODY$
DECLARE r search_type%rowtype;
BEGIN   
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') ORDER BY CONCAT("User_firstname", ' ', "User_lastname") ASC LIMIT "@row_end" OFFSET "@row_start" LOOP
        RETURN NEXT r;
    END LOOP;
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' ORDER BY "Community_name" ASC LIMIT "@row_end" OFFSET "@row_start" LOOP
        RETURN NEXT r;
    END LOOP;
    RETURN;
END
$BODY$
  LANGUAGE plpgsql

然后我将程序称为：

SELECT * FROM search_result('t',3,0)

但没有返回值。

Answer 1

你需要：

SELECT * FROM search_result('c');

不只是：

SELECT search_result('c');

如果你想要一个表格结果。在SELECT 中调用的集合返回函数返回复合元组。