【发布时间】：2021-03-03 09:35:20
【问题描述】：
我有两个 jsonb 值。我想合并它，但是我坚持将它合并在一起。这是我的代码
CREATE OR REPLACE FUNCTION emr.azintin(p_msg text)
RETURNS character varying
LANGUAGE plpgsql
AS $function$
DECLARE
v_msgar text[];
v_msgln text;
v_currusr afm_usr.user_id%type := 'SYSEXCH';
v_currdt afm_usr.insert_date%type := CURRENT_TIMESTAMP;
macres azt_macres%rowtype;
orddet lbt_orddet%rowtype;
v_resultid character varying ;
v_reading character varying ;
BEGIN
v_msgar := array['OBR||||^^^3972^2102001420||||20210227133222|25||||3
OBX|||0^RBC||4.99|^10â¶/μL|3.85-5.78||||F
OBX|||1^HGB||14.4|^g/dL|12.0-17.2||||F
OBX|||2^MCV||84.5|^fL|78.0-96.0||||F
OBX|||3^HCT||42.2|^%|34.8-50.9||||F
OBX|||4^MCH||28.90|^pg|26.40-33.20||||F
OBX|||5^MCHC||34.2|^g/dL|31.8-36.7|||<EOT>|F
OBX|||6^RDWsd||39.2|^fL|0.0-0.0||||F'];
SELECT json_agg(jsonb_build_object('resultValue',split_part(parts[6],'^',1)))
INTO v_reading
FROM unnest(v_msgar) as elem,
regexp_split_to_array(elem, '\|') as parts
WHERE parts[1] = 'OBX';
SELECT json_agg(jsonb_build_object('resultId',split_part(parts[4],'^',2)))
INTO v_resultid
FROM unnest(v_msgar) as elem,
regexp_split_to_array(elem, '\|') as parts
WHERE parts[1] = 'OBX';
select concat(v_resultid || v_reading)
INTO macres.test_result
FROM unnest(v_msgar) as elem,
regexp_split_to_array(elem, '\|') as parts
WHERE parts[1] = 'OBX';
SELECT split_part(items[5], '^', 5)
INTO macres.specimen_id
FROM (
SELECT string_to_array(element, '|') as items
FROM unnest(v_msgar) as t(element)) t
WHERE items[1] = 'OBR';
END IF;
END
$function$
;
我设法得到看起来像这样的 v_reading 和 v_resultid
[{"resultValue": "5.20"}, {"resultValue": "14.2"}, {"resultValue": "81.7"}, {"resultValue": "42.5"}, {"resultValue": "27.20"}, {"resultValue": "33.3"}, {"resultValue": "40.6"}, {"resultValue": "15.9"}, {"resultValue": "188"}, {"resultValue": "8.1"}, {"resultValue": "0.15"}, {"resultValue": "9.4"}, {"resultValue": "46.2"}, {"resultValue": "4.6"}, {"resultValue": "1.1"}, {"resultValue": "23.6"}, {"resultValue": "0.4"}, {"resultValue": "8.7"}, {"resultValue": "3.1"}, {"resultValue": "67.7"}, {"resultValue": "56"}, {"resultValue": "105"}, {"resultValue": ""}]
[{"resultId": "RBC"}, {"resultId": "HGB"}, {"resultId": "MCV"}, {"resultId": "HCT"}, {"resultId": "MCH"}, {"resultId": "MCHC"}, {"resultId": "RDWsd"}, {"resultId": "RDWcv"}, {"resultId": "PLT"}, {"resultId": "MPV"}, {"resultId": "PCT"}, {"resultId": "PDWsd"}, {"resultId": "PDWcv"}, {"resultId": "WBC"}, {"resultId": "LYM"}, {"resultId": "LYMP"}, {"resultId": "MID"}, {"resultId": "MIDP"}, {"resultId": "GRA"}, {"resultId": "GRAP"}, {"resultId": "PLCR"}, {"resultId": "PLCC"}, {"resultId": "RBCHistogram"}]
如何将这两个 json 组合成这样的样子
[{"resultid": "RBC", "resultValue": "5.20"}, {"resultid": "HGB", "resultValue": "5.20"}, {"resultid": "MCV", "resultValue": "5.20"}, {"resultid": "HCT", "resultValue": "5.20"}, {"resultid": "MCH", "resultValue": "5.20"}, {"resultid": "MCHC", "resultValue": "5.20"}, {"resultid": "RDWsd", "resultValue": "5.20"}, {"resultid": "RDWcv", "resultValue": "5.20"}, {"resultid": "PLT", "resultValue": "5.20"}, {"resultid": "MPV", "resultValue": "5.20"}, {"resultid": "PCT", "resultValue": "5.20"}, {"resultid": "PDWsd", "resultValue": "5.20"}, {"resultid": "PDWcv", "resultValue": "5.20"}, {"resultid": "WBC", "resultValue": "5.20"}, {"resultid": "LYM", "resultValue": "5.20"}, {"resultid": "LYMP", "resultValue": "5.20"}, {"resultid": "MID", "resultValue": "5.20"}, {"resultid": "MIDP", "resultValue": "5.20"}, {"resultid": "GRA", "resultValue": "5.20"}, {"resultid": "GRAP", "resultValue": "5.20"}, {"resultid": "PLCR", "resultValue": "5.20"}, {"resultid": "PLCC", "resultValue": "5.20"}, {"resultid": "RBCHistogram", "resultValue": "5.20"}]
我可以简单地做这些
SELECT json_agg(jsonb_build_object('resultid',split_part(parts[4],'^',2), 'resultValue',split_part(parts[6],'^',1)))
INTO macres.test_result
FROM unnest(v_msgar) as elem,
regexp_split_to_array(elem, '\|') as parts
WHERE parts[1] = 'OBX';
但问题是我需要在 split_part(parts[4],'^',2) 中添加一个条件，这就是为什么我将它分成 v_reading 和 v_resultid。
我要设置条件
IF v_resultid = 'MCHC' THEN
v_reading = null
END ID
但不知何故，如果数组找到 MCHC，它仍然会读取读数。我想从我的 json 中删除 MCHC
【问题讨论】：
-
不清楚你在这里做什么。 JSON 值不适合您的数组，该数组无效......所以，这里有两个选项：您是否希望我们编写一个完整的查询（我已经在您之前的问题上做过几次） - 我会这样做在一个查询中，而不是在单独的......或者您只是想知道如何合并两个 JSON 对象。那么请删除整个令人困惑的代码以尽量减少您的问题。
标签： json postgresql stored-procedures merge jsonb