【发布时间】:2020-06-20 21:41:16
【问题描述】:
我正在尝试编写一个 SQL,它可以 pivot 并且还可以在一行中获得它的 ranking 顺序。不知道怎么做。
例子:
旋转area 还可以获得cost 的排名(最贵的顺序)
table name: aaa
entity_id | entity_type | datetime | area | cost
----------+-------------+------+-----+------+-----
123 | ITEM | 2020-01-01 | US | 8
123 | ITEM | 2020-01-01 | AP | 7
123 | ITEM | 2020-01-01 | EU | 6
123 | ITEM | 2020-01-02 | US | 1
123 | ITEM | 2020-01-02 | AP | 2
123 | ITEM | 2020-01-02 | EU | 3
888 | BOX | 2020-01-01 | US | 8
888 | BOX | 2020-01-01 | AP | 7
888 | BOX | 2020-01-01 | EU | 6
888 | BOX | 2020-01-02 | US | 1
888 | BOX | 2020-01-02 | AP | 2
888 | BOX | 2020-01-02 | EU | 3
我想要的是:
entity_id | entity_type | datetime | US | AP | EU | US_rank | AP_rank | EU_rank
----------+-------------+------------+----+----+----+---------+---------+---------
123 | ITEM | 2020-01-01 | 8 | 7 | 6 | 1 | 2 | 3
123 | ITEM | 2020-01-02 | 8 | 7 | 6 | 3 | 2 | 1
888 | BOX | 2020-01-01 | 8 | 7 | 6 | 1 | 2 | 3
888 | BOX | 2020-01-02 | 8 | 7 | 6 | 3 | 2 | 1
目前,我只知道如何旋转。不知道如何获得“排名”部分
SELECT
p.entity_id, p.entity_type, p.[datetime], p.[US], p.[AP], p.[EU]
FROM
aaa as a
PIVOT
(
MAX(cost)
FOR area IN ([US], [AP], [EU])
) p
(which returns)
entity_id | entity_type | datetime | US | AP | EU
----------+-------------+------------+----+----+----
123 | ITEM | 2020-01-01 | 8 | 7 | 6
123 | ITEM | 2020-01-02 | 8 | 7 | 6
888 | BOX | 2020-01-01 | 8 | 7 | 6
888 | BOX | 2020-01-02 | 8 | 7 | 6
我假设我需要在旋转之前将其添加到某处,但不知道在那之后该怎么做
ranking = ROW_NUMBER() OVER(PARTITION BY entity_id, entity_type, [datetime] ORDER BY cost DESC)
(我不介意使用RANK 或ROW_NUMBER 解决这个问题)
【问题讨论】:
标签: sql sql-server pivot row-number ranking-functions