SQL 查询到 JSON答案

【问题标题】：SQL Query to JSONSQL 查询到 JSON
【发布时间】：2016-12-10 01:00:00
【问题描述】：

您好，我是 JSON 新手，想问这个问题：

所以我的目标是让结果看起来像这样：

{
    "userid": "10293304" ,     "segments": ["Online_Flag"]
} 

{
    "userid": "10292298" , "segments": ["schedule_Appointment", "Enrolled_Order","Complete_Order"]

}

我能够使用 T SQL 查询结果如下所示：

[{"userid":"10293159","segments":[{"segment":"Schedule_Appointment"}]},
{"userid":"10293056","segments":[{"segment":"Schedule_Appointment"}]},
{"userid":"10292838","segments":[{"segment":"Schedule_Appointment"}]},

问题是我只需要显示 JSON 值（Schedule_Appointment），而不是键（段）

有没有办法（使用 TSQL）隐藏键并只显示 JSON 数组中的值？

我试图寻找使用 SQL 创建 JSON 数组的方法，但没有运气，如果有人能解释我将不胜感激。

SQL 服务器 2016

数据

CREATE TABLE [dbo].[Lotame_JSON](
[lead_id] [varchar](100) NULL,
[dist_date_key] [date] NULL,
[online_flag] [int] NULL,
[sched_appt_qty] [int] NULL,
[enroll_order_qty] [int] NULL,
[compl_order_qty] [int] NULL)

insert into [dbo].[Lotame_JSON]
values('105646','2016-12-1',1,0,0,1)

insert into [dbo].[Lotame_JSON]
values('125646','2016-12-1',0,0,1,0)

insert into [dbo].[Lotame_JSON]
values('112646','2016-12-1',0,1,1,0)

insert into [dbo].[Lotame_JSON]
values('106446','2016-12-1',0,0,1,0)

我有疑问：

select 
[lead_id] AS 'userid',
(
SELECT segment
    from 
    (
        SELECT              
            CASE WHEN [online_flag] > 0 THEN '1' else null end as 'online_flag',
            CASE WHEN sched_appt_qty > 0 THEN '2' else null end as 'Schedule_Appointment',
            CASE WHEN enroll_order_qty > 0 THEN '3'  else null end as 'Enrolled_Order',
            CASE WHEN compl_order_qty > 0 THEN '4'  else null end as 'Complete_Order'
        FROM [dbo].[Lotame_JSON] as sub
        WHERE sub.lead_id = main.lead_id
    ) t
    UNPIVOT
    (
        segment1
        for segment in (online_flag,Schedule_Appointment,Enrolled_Order,Complete_Order)
    ) as UnPvot
    for JSON PATH
) AS 'segments' 
from [dbo].[Lotame_JSON] as main
where online_flag = 0 and (sched_appt_qty > 0 or enroll_order_qty > 0   or    compl_order_qty > 0)
and dist_date_key >= '2016-9-1'
FOR JSON PATH

谢谢

【问题讨论】：

您使用的是哪个版本的SQL SERVER？
您也可以添加您已经使用的查询来获得到目前为止的结果。
已更新，感谢您的帮助！！
在这里发布代码、数据或查询结果的图像而不是文本被认为是非常不礼貌的。
@JoelCoehoorn 已更新，感谢您的建议，您太好了

标签： sql sql-server json sql-server-2016

【解决方案1】：

你很亲密。有一个技巧可以在 SQL 中正确格式化 JSON 数组。您可以对数组中所需的数据使用JSON_QUERY、STUFF 和FOR XML PATH 的组合。要获得没有最外面方括号的结果，请使用FOR JSON PATH, WITHOUT_ARRAY_WRAPPER。把它们放在一起，你会得到一个如下所示的查询：

SELECT 
userid = [lead_id]
,segments = JSON_QUERY(
                        '[' + STUFF(
                                    (
                                        SELECT ',' + '"' +  segment + '"'
                                        FROM
                                        (
                                            SELECT              
                                                CASE WHEN [online_flag] > 0 THEN '1' ELSE NULL END AS 'online_flag',
                                                CASE WHEN sched_appt_qty > 0 THEN '2' ELSE NULL END AS 'Schedule_Appointment',
                                                CASE WHEN enroll_order_qty > 0 THEN '3' ELSE NULL END AS 'Enrolled_Order',
                                                CASE WHEN compl_order_qty > 0 THEN '4' ELSE NULL END AS 'Complete_Order'
                                            FROM [dbo].[Lotame_JSON] AS sub
                                            WHERE sub.lead_id = main.lead_id
                                        ) t
                                        UNPIVOT
                                        (
                                            segment1 FOR segment IN (online_flag, Schedule_Appointment, Enrolled_Order, Complete_Order)
                                        ) AS UnPvot
                                        FOR XML PATH ('')
                                    )
                        , 1, 1, '') + ']'
                    )
FROM [dbo].[Lotame_JSON] AS main
WHERE online_flag = 0
    AND dist_date_key >= '2016-9-1'
    AND (
            sched_appt_qty > 0 
            OR enroll_order_qty > 0
            OR compl_order_qty > 0
        )
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER

【讨论】：