SQL 生成不带方括号的 JSON

Question

我有这个问题：

SELECT 
    'Ball' AS title, 'Blue' AS color, 
    (SELECT '1' AS Opt1, '2' AS Opt2 
     FOR JSON PATH) AS 'Options'
FOR JSON PATH, ROOT('product')

我得到了这个非常好的 JSON，但在 product（标记）之后我不能有括号

{"product": 
[  <======
{
 "title": "Ball",
 "color": "Blue",
 "Options": [{"Opt1": "1","Opt2": "2"}]
}
]  <======
}

换句话说，我需要这个：

{"product": 
{
 "title": "Ball",
 "color": "Blue",
 "Options": [{"Opt1": "1","Opt2": "2"}]
}
}

我不能使用WITHOUT_ARRAY_WRAPPER 选项，因为我已经使用了ROOT 选项。 我应该怎么做才能删除这些方括号？

Answer 1

非常接近 Greg Low 的答案，但用 json_query 包裹内部选择以避免自动转义（这是因为使用了选项 without_array_wrapper）：

SELECT JSON_QUERY((
    SELECT 'Ball' AS title, 
           'Blue' AS color, (
                select '1' AS Opt1, 
                       '2' AS Opt2 
                FOR JSON PATH
           ) as Options
    FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
    )) AS Product
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER;

这会给你想要的结果 -

{
  "Product": {
    "title": "Ball",
    "color": "Blue",
    "Options": [
      {
        "Opt1": "1",
        "Opt2": "2"
      }
    ]
  }
}

Answer 2

这就是你所追求的吗？

SELECT (SELECT 'Ball' AS title, 
               'Blue' AS color, 
               (select '1' AS Opt1, '2' AS Opt2 FOR JSON PATH) as 'Options'
        FOR JSON PATH, WITHOUT_ARRAY_WRAPPER) AS Product
        FOR JSON PATH, WITHOUT_ARRAY_WRAPPER;