【发布时间】:2016-11-18 12:11:43
【问题描述】:
我要执行程序并获取输出参数
import pypyodbc
command = "DECLARE @l_Stat INT \r\n" \
"DECLARE @s_Ms VARCHAR(200) \r\n" \
"EXEC p_Log_InsertParam_2011v1 " \
"@l_TesterId=?, " \
"@l_ObiektId=?, " \
"@l_RejPId=?, " \
"@s_ParamName=?, " \
"@f_ParamValue=?, " \
"@f_ParamMinValue=?, " \
"@f_ParamMaxValue=?, " \
"@b_CheckParam=?, " \
"@l_Status=@l_Stat output, " \
"@s_Msg=@s_Ms output \r\n" \
"SELECT @l_Stat, @s_Ms\r\n"
connection = pypyodbc.connect(self.ConnectionString)
cursor = connection.cursor()
params=(453879185, 23192812, 645872, '/APL/CTRL_GZ/PID/SP', 35.0, 0, 0, True)
# params = (testerid,
# obiektid,
# rejpid,
# paramname,
# paramvalue,
# paramminvalue,
# parammaxvalue,
# checkparam) """
result = cursor.execute(command, params)
pars = result.fetchall()[0]
print pars
if pars.__len__() >= 2:
l_status = pars[0]
s_msg = pars[1]
print "{}: {};".format(l_status, s_msg)
它运行良好到result = cursor.execute(command, params) 行 - 程序正确执行。
当我尝试在pars = result.fetchall()[0] 行中获取结果时出现问题:
u'24000', u'[24000] [Microsoft][ODBC SQL Server Driver]Invalid Cursor State'
我怎样才能摆脱这个错误?
【问题讨论】:
-
这是否与字符编码有关? u24000 可能是character code for this HAN-symbol。这样的 far-east-characters 往往会在
UTF-8等编码中产生奇怪的问题,它们的编码需要三个字节,有时甚至是四个字节。有几个工具无法解决这个问题。 -
@Shnugo - 我不这么认为。
标签: python sql-server python-2.7 stored-procedures pypyodbc