C# XML 序列化 - 更改数组项名称答案

【问题标题】：C# XML serialization - Change array item nameC# XML 序列化 - 更改数组项名称
【发布时间】：2023-03-20 08:30:01
【问题描述】：

我需要将具有 List 属性的对象序列化为 XML 以获得这样的 XML 代码（我知道它不是有效的 XML，但我的第 3 方应用程序需要这种格式）：

<Filters>
    <Criteria_0 Parameter="STATUS"
        Operator="EQUAL"
        Value="STARTED" />
    <Criteria_1 Parameter="STATUS" 
        Operator="EQUAL"
        Value="COMPLETED" />
</Filters>

我写了这样的代码：

public class JobStatusListTask
{
    public JobListSettings ListSettings;

    public List<JobFilterCriteria> Filters;

    public JobStatusListTask()
    {
        Filters = new List<JobFilterCriteria>();
        Filters.Add(new JobFilterCriteria("STATUS", CriteriaOperator.Equal, "ERROR"));
    }


    public JobStatusListTask(JobListSettings settings) : this()
    {
        ListSettings = settings;
    }
}

public class JobFilterCriteria : IXmlSerializable
{
    public static int Count = 0;

    public string Parameter;

    public CriteriaOperator Operator;

    public string Value;

    private JobFilterCriteria()
    {
        Parameter = string.Empty;
        Value = string.Empty;
    }

    public JobFilterCriteria(string parameter, CriteriaOperator criteriaOperator, string value)
    {
        Parameter = parameter;
        Operator = criteriaOperator;
        Value = value;
    }

    XmlSchema IXmlSerializable.GetSchema()
    {
        return null;
    }

    void IXmlSerializable.ReadXml(XmlReader reader)
    {
        throw new NotImplementedException();
    }

    void IXmlSerializable.WriteXml(XmlWriter writer)
    {
        writer.WriteStartElement(string.Format("Criteria_{0}", Count++));
        writer.WriteAttributeString("Parameter", Parameter);
        writer.WriteAttributeString("Operator", Operator.ToString());
        writer.WriteAttributeString("Value", Value);
    }
}

它工作得几乎完美。序列化程序返回带有不必要 JobFilterCriteria 元素的 XML 代码。

<?xml version="1.0" encoding="utf-8"?>
<Filters>
    <JobFilterCriteria>
        <Criteria_0 
            Parameter="STATUS" Operator="Equal" Value="ERROR" />
    </JobFilterCriteria>
    <JobFilterCriteria>
        <Criteria_1 
            Parameter="STATUS" Operator="Equal" Value="STARTED" />
    </JobFilterCriteria>
</Filters>

从 XML 代码中删除 JobFilterCriteria 需要进行哪些更改？

【问题讨论】：

标签： c# .net xml xml-serialization

【解决方案1】：

我想，这个代码块会解决你的问题，你需要序列化 JobStatusListTask 类。

public class JobStatusListTask : IXmlSerializable
{
    public JobListSettings ListSettings;

    public List<JobFilterCriteria> Filters;

    public JobStatusListTask()
    {
        Filters = new List<JobFilterCriteria>();
        Filters.Add(new JobFilterCriteria("STATUS", CriteriaOperator.Equal, "ERROR"));
    }


    public JobStatusListTask(JobListSettings settings) : this()
    {
        ListSettings = settings;
    }

    public void WriteXml(XmlWriter writer)
    {
        writer.WriteStartElement("Filters");
        foreach(var item in Filters)
        {
            writer.WriteStartElement("Criteria", string.Format("Criteria_{0}", Count++));
            writer.WriteAttributeString("Parameter", Parameter);
            writer.WriteAttributeString("Operator", Operator.ToString());
            writer.WriteAttributeString("Value", Value);
        }
        writer.WriteEndElement();
    }

}

【讨论】：

【解决方案2】：

我无法对答案发表评论，但我看不到上面的编译方式是如何按原样编译的，而且似乎命名空间是被意外设置的，我相信你已经解决了，但为了后代，有一些变化我认为需要使其按预期工作：

public class JobStatusListTask : IXmlSerializable
{
    public JobListSettings ListSettings;

    public List<JobFilterCriteria> Filters;

    public JobStatusListTask()
    {
        Filters = new List<JobFilterCriteria>();
        Filters.Add(new JobFilterCriteria("STATUS", CriteriaOperator.Equal, "ERROR"));
    }


    public JobStatusListTask(JobListSettings settings) : this()
    {
        ListSettings = settings;
    }

    public void WriteXml(XmlWriter writer)
    {
        writer.WriteStartElement("Filters");
        for(int i = 0; i < Filters.Count; i++)
        {
            writer.WriteStartElement(string.Format("Criteria_{0}", i));
            writer.WriteAttributeString("Parameter", Parameter);
            writer.WriteAttributeString("Operator", Operator.ToString());
            writer.WriteAttributeString("Value", Value);
        }
        writer.WriteEndElement();
    }

}

【讨论】：